Question

我正在尝试将元素值未知或元素数量未知的元素输入数组

public class Sales
{
  public void salesAmount()
  {
Scanner scan = new Scanner(System.in);

int sum = 0; 
int salespeople = 0;

    //Create printstatement to ask the user to ("enter the number of sales people");
   System.out.println("Enter the number of sales people: ");


   //store the response in salespeople
   salespeople = scan.nextInt();


    //Create an int array called sales that will have the number entered by user as the number of elements
    int[] sales = new int[salespeople];


    //create a for loop that will loop through the array sales.    
    for(int i = 0; i < salespeople; i++)
{
     //Create print statement that says:  ("Enter sales for salesperson " + i + ": ");
      System.out.println("Enter sales for salesperson " + i + ": ");
      sales[i] = scan.nextInt();
      //store response in sales[i] 
      sum = sum + sales[i];

    }

    System.out.println("Salesperson\tSales");
    System.out.println("--------------------");

    for (int i=0; i<sales.length; i++)
    { 
      System.out.println(i + "\t" + sales[i]); 
      sum += sales[i];
    }

    System.out.println("\nTotal sales: " + sum);
      }
    }

我将所有内容打印在第二个文件中，这是下面的代码：

public static void main(String[]args)
{
  Sales sales = new Sales();
  sales.salesAmount();
}

预期结果应该是所有输入数字的总和，但是我的结果是它们的总和，然后加倍。

Answer 1

在第二个“ for循环”中，删除总和。您会在2个循环中进行两次加法操作

for (int i=0; i<sales.length; i++)
    { 
      System.out.println(i + "\t" + sales[i]); 
      //sum += sales[i];
    }

    System.out.println("\nTotal sales: " + sum);

Answer 2

问题是您将总和加倍两次，一次遍历销售人员：

sum = sum + sales[i];

然后再打印总销售额：

for (int i=0; i<sales.length; i++)
{ 
  System.out.println(i + "\t" + sales[i]); 
  sum += sales[i];
}

因此，您需要在第二个循环之前重设总和-即sum = 0;，或者从第二个循环中删除行sum += sales[i];。

将元素输入数组

2 个答案: