Question

在我的课堂上，我想调用一个非成员函数，其引用存储在成员变量中。我的问题是它试图将self传递给函数作为第一个参数。如何避免这种情况？

class MyClass:
    my_useful_static_function = crcmod.mkCrcFun(0x11021, True)

    def __init__(self):
        # this gets called with the first argument as self :(
        result = self.my_useful_static_function()

Answer 1

使用staticmethod：

class MyClass:
    my_useful_static_function = staticmethod(crcmod.mkCrcFun(0x11021, True))

    def __init__(self):
        result = self.my_useful_static_function()

Answer 2

您需要像这样使用staticmethod：

class Foo: 
    @staticmethod 
    def my_method(): 
        print("This is a static method") 

    def my_other_method(self): 
        print("This is not static")

# This works
Foo.my_method()

# This won't work
Foo.my_other_method()

# This works though
foo_instance = Foo()
foo_instance.my_other_method()

调用类变量引用的Python非成员函数

2 个答案: