Question

我正在阅读xml。从这个xml中，我将4个参数存储到数组中。

如何将这些数组组合成一个foreach循环，以便可以将这些数据存储到SQL中并使用它们？

我设法为两个数组创建.Zip。是否可以像这样组合4个数组？基本上，我想将 id 和 recDate 添加到numbersAndWords数组中。

XmlDocument doc = new XmlDocument();

        doc.LoadXml(result);

        var cislo = new List<string>();
        var zprava = new List<string>();
        var id = new List<string>();
        var recDate = new List<string>();

        XmlNodeList number = doc.GetElementsByTagName("SenderNumber");
        for (int i = 0; i < number.Count; i++)
        {
            cislo.Add(number[i].InnerXml);
        }

        XmlNodeList text = doc.GetElementsByTagName("TextDecoded");
        for (int i = 0; i < text.Count; i++)
        {
            zprava.Add(text[i].InnerXml);
        }

        XmlNodeList idNum = doc.GetElementsByTagName("ID");
        for (int i = 0; i < idNum.Count; i++)
        {
            id.Add(idNum[i].InnerXml);
        }

        XmlNodeList recDateTime = doc.GetElementsByTagName("ReceivingDateTime");
        for (int i = 0; i < recDateTime.Count; i++)
        {
            recDate.Add(recDateTime[i].InnerXml);
        }



        var numbersAndWords = cislo.Zip(zprava, (n, w) => new {Number = n, Word = w});
        cs.Open();
        foreach (var nw in numbersAndWords)
        {
            MessageBox.Show(nw.Number);
            MessageBox.Show(nw.Word);
        }

Answer 1

尝试使用以下方法组合这些数组：

private static T[] Combine<T>(params IEnumerable<T>[] items) =>
                              items.SelectMany(i => i).Distinct().ToArray();

并使用它：

var combinedArrays = Combine(cislo, zprava, id, recDate);

for (int i = 0; i < combinedArrays.Length; i++)
{
    MessageBox.Show(i);
    MessageBox.Show(combinedArrays[i]);
}

如果您要在中执行sql语句，则创建新类并用数据填充它会很好。例如：

public class Item
{
   public string Id { get; set; }
   public string Cislo { get; set; }
   public string Zprava { get; set; }
   public string RecDate { get; set; }
}

var items = id.Select((id, index) => new Item() 
                                       {
                                          Id = id,
                                          Cislo = cislo[index],
                                          Zprava = zprava[index],
                                          RecDate = recDate[index]                                             
                                        }).ToList();

foreach (var item in items)
{
   string sql = " insert into contacts(id, zprava, cislo) values (@id, @zprava, @cislo)";

   var command = new SqlCommand(sql, connection);

   // bind the parameters in the sql based on the `item` object.
   // execute the command, etc..
}

Answer 2

如果您确定所有元素数均相等，请创建类并填写：

class Record
{
   public string cislo;
   public string zprava;
   public string id;
   public string recDate;
}
.....
List<Record> records = new List<Record>();
    XmlNodeList number = doc.GetElementsByTagName("SenderNumber");
    for (int i = 0; i < number.Count; i++)
    {
       records.Add(new Record { cislo = number[i].InnerXml });
    }

    XmlNodeList text = doc.GetElementsByTagName("TextDecoded");
    for (int i = 0; i < text.Count; i++)
    {
        records[i].zprava = text[i].InnerXml;
    }

等

Answer 3

您可以使用Zip的实现来压缩四个可枚举，并返回一个ValueTuple<T, T, T, T>元素的可枚举：

public static IEnumerable<(T, T, T, T)> Zip4<T>(IEnumerable<T> source1,
    IEnumerable<T> source2,
    IEnumerable<T> source3,
    IEnumerable<T> source4)
{
    using (IEnumerator<T> e1 = source1.GetEnumerator(),
        e2 = source2.GetEnumerator(),
        e3 = source3.GetEnumerator(),
        e4 = source4.GetEnumerator())
    {
        while (e1.MoveNext() && e2.MoveNext() && e3.MoveNext() && e4.MoveNext())
        {
            yield return (e1.Current, e2.Current, e3.Current, e4.Current);
        }
    }
}

用法示例：

foreach (var combo in Zip4(cislo, zprava, id, recDate))
{
    Console.WriteLine($"{combo.Item1}-{combo.Item2}-{combo.Item3}-{combo.Item4}");
}

如何压缩4个或更多数组

3 个答案: