Question

我有一个包含对象的数组，我想将对象内部的所有params值合并为一个对象

wide <- do.call(cbind, mylist_new)
rowMeans(wide[names(wide) == "C"])
# [1] 2.0 6.5

我已经尝试过了

Array [
  Object {
    "key": "Deze week",
    "params": Object {
      "thisWeekfilterDistance": [Function anonymous],
      "thisWeekSearch": [Function anonymous],
      "thisWeektoggleFilter": [Function anonymous],
      "thisWeektoggleRangeFilter": [Function anonymous],
    },
    "routeName": "Deze week",
  },
  Object {
    "key": "Binnenkort",
    "params": Object {
      "soonfilterDistance": [Function anonymous],
      "soonSearch": [Function anonymous],
      "soontoggleFilter": [Function anonymous],
      "soontoggleRangeFilter": [Function anonymous],
    },
    "routeName": "Binnenkort",
  },
  Object {
    "key": "Festivals",
    "params": Object {
      "festivalfilterDistance": [Function anonymous],
      "festivalSearch": [Function anonymous],
      "festivaltoggleFilter": [Function anonymous],
      "festivaltoggleRangeFilter": [Function anonymous],
    },
    "routeName": "Festivals",
  },
]

或

for (var i = 0; i < 3; i++) {
        if (typeof arr[i].params !== 'undefined') {
            //console.log(arr[i].params);
            test = arr[i].params;
        }
    }

但是我不知道如何存储那些结果以使所有对象参数只有1个对象。

所以预期结果是：


for (var i = 0; i < 3; i++) {
   arr[i].param.reduce(function(result, current) {
     return Object.assign(result, current);
   }, {})
}

谢谢。

Answer 1

您可以使用map来获取params的数组。然后使用Object.assign()将对象数组合并为一个对象：

const input = [{"key":"Deze week","params":{"thisWeekfilterDistance":_=>{},"thisWeekSearch":_=>{},"thisWeektoggleFilter":_=>{},"thisWeektoggleRangeFilter":_=>{},},"routeName":"Deze week",},{"key":"Binnenkort","params":{"soonfilterDistance":_=>{},"soonSearch":_=>{},"soontoggleFilter":_=>{},"soontoggleRangeFilter":_=>{},},"routeName":"Binnenkort",},{"key":"Festivals","params":{"festivalfilterDistance":_=>{},"festivalSearch":_=>{},"festivaltoggleFilter":_=>{},"festivaltoggleRangeFilter":_=>{},},"routeName":"Festivals",},]

const output = Object.assign({}, ...input.map(a => a.params))
console.log(output)

Answer 2

您可以使用Array#reduce直接数组而不使用数组对象参数

var arr = [{ "key": "Deze week", "params":  { "thisWeekfilterDistance": "[Function anonymous]", "thisWeekSearch": "[Function anonymous]", "thisWeektoggleFilter": "[Function anonymous]", "thisWeektoggleRangeFilter": "[Function anonymous]", }, "routeName": "Deze week", }, { "key": "Binnenkort", "params":  { "soonfilterDistance": "[Function anonymous]", "soonSearch": "[Function anonymous]", "soontoggleFilter": "[Function anonymous]", "soontoggleRangeFilter": "[Function anonymous]", }, "routeName": "Binnenkort", }, { "key": "Festivals", "params":  { "festivalfilterDistance": "[Function anonymous]", "festivalSearch": "[Function anonymous]", "festivaltoggleFilter": "[Function anonymous]", "festivaltoggleRangeFilter": "[Function anonymous]", }, "routeName": "Festivals", }, ]

var res = arr.reduce((a,b)=> Object.assign(a,b.params),{})

console.log(res)

如何在对象数组中合并深度值

2 个答案: