我是Android Studio的新手,并且在解析JSON时遇到问题。 这是我的JSON:
List<WebElement> amtButton = driver.findElements(By.xpath("//select[@id='amt']"));
if(amtButton.size()==1){
amtButton.get(0).click();
}
我尝试这样解析它:
[{
id: 304,
Title: "Anna and the Apocalypse",
Year: "2017",
Released: "30 Nov 2018",
Runtime: "93 min",
Genre: "Comedy, Fantasy, Horror, Musical",
Director: "John McPhail",
Writer: "Alan McDonald, Ryan McHenry",
Actors: "Ella Hunt, Malcolm Cumming, Sarah Swire, Christopher Leveaux",
Language: "English",
Country: "UK",
Awards: "1 nomination.",
PosterLow: "http://movie30t.co/wp-content/themes/m30t/timthumb.php?src=http://movie30t.co/wp-content/uploads/2018/09/Anna-and-the-Apocalypse-2017.jpg&h=200%&w=133&zc=0",
PosterHigh: "http://movie30t.co/wp-content/themes/m30t/timthumb.php?src=http://movie30t.co/wp-content/uploads/2018/09/Anna-and-the-Apocalypse-2017.jpg&h=700%&w=500%&zc=0",
IMDBScore: "6.2",
Production: "Orion Pictures",
DL720pLink: "http://dl2.hostgig.ir/dl/f/Anna%20and%20the%20Apocalypse%202018/Anna%20and%20the%20Apocalypse%202018%20720p%20BRRip%20MOVIE30T.CO.mkv",
DL1080pLink: "N/A",
SubtitleLink: "N/A",
DLDubLink: "N/A",
State: "True",
Status: "Active",
ViewCount: "157",
VoteLike: "0",
VoteDisslike: "0",
TrailerLink: "http://dl2.hostgig.ir/dl/t/f/Anna and the Apocalypse 2018/Anna and the Apocalypse 2018.mp4",
Response: true,
Type: "Movie"
}]
我收到以下错误:
类型org.json.JSONArray无法转换为JSONObject
我知道我需要使用RequestQueue queue = new Volley().newRequestQueue(this);
final JsonObjectRequest jsonArrayRequest = new JsonObjectRequest(Request.Method.GET, url, null,
new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
Gson gson = new Gson();
MovieModel movieModel = gson.fromJson(response.toString(), MovieModel.class);
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(MainActivity.this, error.toString(), Toast.LENGTH_SHORT).show();
}
});
queue.add(jsonArrayRequest);
而不是JsonArrayRequest
,但是我不知道该如何获取对象?
我搜索了其他帖子,但听不懂!
您能帮我学习吗?
答案 0 :(得分:1)
RequestQueue queue = new Volley().newRequestQueue(this);
final JsonObjectRequest jsonArrayRequest = new JsonObjectRequest(Request.Method.GET, url, null,
new Response.Listener< JSONArray>() {
@Override
public void onResponse(JSONArray response) {
Gson gson = new Gson();
List<MovieModel> movieModels = gson.fromJson(response.toString(), List.class);
MovieModel movieModal = movieModels.get(0);
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(MainActivity.this, error.toString(), Toast.LENGTH_SHORT).show();
}
});
queue.add(jsonArrayRequest);
答案 1 :(得分:0)
您已经将response
作为JSONArray
。
因此,您可以致电
JSONObject jresponse = response.getJSONObject(0);
在onResponse
内部分析您的回复。
JSONObject jresponse = response.getJSONObject(0);
String title= jresponse.getString("Title");
Log.d("title", title);
我希望这会对您有所帮助。