我尝试将某些位与c中uint8_t类型的数组连接起来,例如:
int main(int argc, char **argv) {
if(argc < 2) {
printf("Usage: %s <Input _message>\n", argv[0]);
return -1;
}
uint8_t L_length_of_message =strlen(argv[1]);
num_0's_in_bits_addedd=13; // try to || 13 bit with array
uint8_t msg[L_length_of_message];
//assume this msg is already converted in hex format
现在i,e msg = 0xabcf123; 我想将13(bits)与msg i,e连接;
msg=0xabcf123;
msg_in_bits=1010101111001111000100100011
zeors_added_in_bits=0000000000000;
new_msg_in_bits=10101011110011110001001000110000000000000;
new_msg=0x1579e246000
主要问题是消息存储在char数组中,因此多位的移位操作不起作用。为该问题提出一些解决方案?