Question

我当前的程序遇到了麻烦，该程序应该从用户输入中提取字母，对照我已有的字典文件检查它们，然后返回可以由一系列字母组成的可能的单词。然后，应该由用户输入来指示实际返回了多少个单词。我是python的新手，在如何根据字典文件检查字母时遇到麻烦。我将非常感谢您提供的所有帮助！

这是我到目前为止所拥有的：

def find_words (letters, dictionary):
    dictionary = open ('enable1.txt', 'r')
    r = dictionary.read()
    dictionary.close()
    dict = dictionary (word)
    w = 1
    for k in dict.keys():
        if k not in dictionary:
            w = 0
        if w == 1:
            print (word)

print (find_words (['e', 'u', 'c', 'i']))

def main ():
    letters = int (input ("please enter some letters... at least 1, but no more than 7\n>"))
    if letters < 1 and letters > 7:
        print (letters)
    try:    
       num_words = int (input ("What is the maximum number of words to display?\n>"))
  except ValueError:
       print ()

所需的输出应如下所示：

Please enter some letters... at least 1, but no more than 7
> 123
Please enter some letters... at least 1, but no more than 7
>
Please enter some letters... at least 1, but no more than 7
> abcdefghijklmnop
Please enter some letters... at least 1, but no more than 7
> tdri

What is the maximum number of words to display?
> 1
Showing max 1 results:
dirt

Answer 1

这是查找输入字符的字谜的函数的有效示例。您可以放入一个计数器，并在需要时使用break退出循环。我相信用户输入可以正常工作

dictionary_file = '/usr/share/dict/american-english' # Ubuntu's dictionary file

def anagrams(chars, dictionary_file):

    with open(dictionary_file) as f:

        # iterate through the dictionary file one line at a time
        for line in f:

            # Check to see that all characters are in there and the length matches
            if all(c in line for c in chars) and (len(line.strip()) == len(chars)):

                # Present the match
                print(line.strip())


anagrams('ritd', dictionary_file)
# dirt

如果要捕获结果然后以其他方式处理它们，可以将print()更改为yield并遍历生成器。（这就像在range(42)上进行迭代。

def anagrams(chars, dictionary_file):

    with open(dictionary_file) as f:
        for line in f:
            if all(c in line for c in chars) and (len(line.strip()) == len(chars)):
                yield line.strip()


for match in anagrams('ritd', dictionary_file):
    print(match)
# dirt

该程序接收用户的一组字母并从单独的词典文件中打印出有效单词的所有组合

1 个答案: