我正在尝试在NSDictionary中显示每个项目。我尝试过使用for循环但是没有用。
答案 0 :(得分:58)
试试此代码
for(NSString *key in [dict allKeys]) {
NSLog(@"%@",[dict objectForKey:key]);
}
答案 1 :(得分:25)
怎么样?
NSLog(@"Dictionary: %@", [myDictionary description]);
似乎为我工作......
答案 2 :(得分:0)
如果你想将它保存在NSString上,你可以使用
NSMutableString *stringUserInfo = [[NSMutableString alloc] init];
for (NSString *aKey in dictionary.allKeys)
[stringUserInfo appendFormat:@"%@ : %@\n",aKey,[dictionary valueForKey:aKey]];
答案 3 :(得分:0)
*Try this simple example:
//.h file
@interface DictionaryClass : NSObject
{
NSDictionary *dict;
}
-(void) intialiseDictionary;
-(void) displayDictonary;
-------------------------------------------------------
//.m file
#import "DictionaryClass.h"
@implementation DictionaryClass
-(void) intialiseDictionary
{
dict = @{@"key1":@"object1",@"key2":@"object2",@"key3":@"object3",@"key4":@"object4"};
}
-(void) displayDictonary
{
for(NSString *keys in dict)
{
NSLog(@"\n Dictionary object = %@",[dict objectForKey:keys]);
}
}
@end
-------------------------------------------------------
//main function
#import <Foundation/Foundation.h>
#import "DictionaryClass.h"
int main(int argc, const char * argv[])
{
@autoreleasepool
{
DictionaryClass *obj = [[DictionaryClass alloc]init];
[obj intialiseDictionary];
[obj displayDictonary];
}
return 0;
}*
答案 4 :(得分:-1)
这对我有用,对调试非常有用。
NSDictionary * jsonDictionary = [theJSON JSONValue];
NSLog(@"dictionary data %@",jsonDictionary);
答案 5 :(得分:-2)
我认为您可以使用
打印NSDictionaryNSLog(@“nsdic =%@”,dic);
希望得到它的帮助。