Question

while number = int(1,20):
    print ("What grocery would you like to purchase?")

终端错误：

myclient = pymongo.MongoClient("mongodb://localhost:27017/")
mydb = myclient["game"]
mycol = mydb["test_collection"]


class ProcessWork:
    res1 = []
    res2 = []

    def processwork1(request, res1):
        country = request.GET.get('country')
        qry = {'country': country}
        query = mycol.find(qry).limit(10)
        result = json.loads(dumps(query))
        res1.append(result)

    def processwork2(request, res2):
        country = request.GET.get('country')
        qry = {'country': country}
        query = mycol.find(qry).skip(10).limit(10)
        result = json.loads(dumps(query))
        res2.append(result)

    def process(request):
        t1 = multiprocessing.Process(target=ProcessWork.processwork1, args=((request), ProcessWork.res1))
        t2 = multiprocessing.Process(target=ProcessWork.processwork1, args=((request), ProcessWork.res2))

        t1.start()
        t1.join()
        t2.start()
        t2.join()
        # result = ProcessWork.res1[0] + ProcessWork.res2[0]
        return JsonResponse({})

在这里，我正在使用多重处理在python中运行多个任务。我正在使用pymongo客户端从mongodb获取数据。

我无法理解这个错误。由于这个结果，我也没有得到结果。

请看看

Answer 1

您是否尝试过在processwork2()和processwork1()方法中创建Mongo连接？

您正在fork()系统调用发生之前创建MongoClient（可能是OS创建新进程的一部分）。

只需将此部分放在方法主体中即可

myclient = pymongo.MongoClient("mongodb://localhost:27017/")
mydb = myclient["game"]
mycol = mydb["test_collection"]

MongoClient在派生之前打开。仅创建MongoClient

1 个答案: