Question

作为较大的select查询的一部分，我需要从json数组的对象中提取值作为逗号分隔的字符串。

我设法从json对象中获取了json数组：

SELECT * FROM (SELECT json_extract(Site.Login, '$.Uris') FROM Site);

第二个变体给出相同的结果：

SELECT value FROM json_each(Site.Login), Site WHERE json_each.key = 'Uris';

单行给出所需结果的测试：

SELECT group_concat(json_extract(value, '$.Uri')) as login_uri FROM json_each('[{"Uri":"https://cnn.com"},{"Uri":"https://bbc.com"},{"Uri":"https://reuters.com"}]');

我迷失在矩阵中。我已经尝试了多种方法来组合上面的查询代码，但是我没有任何进展。

Site.Login单元的示例。 Uri对象的数量可以从0到无限。

{
    "Uris": [
            {"Uri":"https://cnn.com"},
            {"Uri":"https://bbc.com"},
            {"Uri":"https://reuters.com"}
    ],
    "Username": "ghhhhhhhhhhhhhfgggggggggggggggg",
    "Password": "hgfhfghfghfgh",
    "PasswordRevisionDate": "2019-01-07T21:51:42.65Z",
    "Totp": "gffffffffffffffffffffffhhhhhhhhhhhhhhhfghghgfh",
    "Name": "hgfhfghfghfghfgh",
    "PasswordHistory": [
        {
            "Password": "ghfghfghfghfghfg",
            "LastUsedDate": "2019-01-07T21:51:42.65Z"
        }
    ]
}

“网站”表的完整布局：

CREATE TABLE "Site" (
"Id" varchar primary key not null ,
"FolderId" varchar ,
"UserId" varchar ,
"OrganizationId" varchar ,
"Name" varchar ,
"Notes" varchar ,
"Fields" varchar ,
"PasswordHistory" varchar ,
"Login" varchar ,
"Card" varchar ,
"Identity" varchar ,
"SecureNote" varchar ,
"Favorite" integer ,
"Edit" integer ,
"OrganizationUseTotp" integer ,
"RevisionDateTime" bigint ,
"Type" integer ,
"Data" varchar )

select查询应返回一个名为login_uri的列，其中包含提取的json数组对象值作为连接字符串： https://cnn.com,https://bbc.com,https://reuters.com

Answer 1

您非常亲密！

SELECT group_concat(json_extract(j.value, '$.Uri')) AS login_uri
FROM site AS s
JOIN json_each(json_extract(s.login, '$.Uris')) AS j

给予

login_uri                                          
---------------------------------------------------
https://cnn.com,https://bbc.com,https://reuters.com

如果您希望表中的每一行都给出结果行，而不是将整个表中的 all uris连接在一起成为一个字符串，请在末尾添加GROUP BY s.id

如何在SQLite

1 个答案: