我想用php上传一个csv文件。上传文件后，我想显示CSV文件的数据。我想举例说明如何完成这项任务。
答案 0 :(得分：103)
现在可以用更简单的方式完成。
$tmpName = $_FILES['csv']['tmp_name'];
$csvAsArray = array_map('str_getcsv', file($tmpName));
这将返回一个已解析的CSV数据数组。然后你可以使用foreach语句循环遍历它。
答案 1 :(得分：61)
未经测试但应该给你这个想法。观点：
<form action="upload.php" method="post" enctype="multipart/form-data">
<input type="file" name="csv" value="" />
<input type="submit" name="submit" value="Save" /></form>
upload.php控制器：
$csv = array();
// check there are no errors
if($_FILES['csv']['error'] == 0){
$name = $_FILES['csv']['name'];
$ext = strtolower(end(explode('.', $_FILES['csv']['name'])));
$type = $_FILES['csv']['type'];
$tmpName = $_FILES['csv']['tmp_name'];
// check the file is a csv
if($ext === 'csv'){
if(($handle = fopen($tmpName, 'r')) !== FALSE) {
// necessary if a large csv file
set_time_limit(0);
$row = 0;
while(($data = fgetcsv($handle, 1000, ',')) !== FALSE) {
// number of fields in the csv
$col_count = count($data);
// get the values from the csv
$csv[$row]['col1'] = $data[0];
$csv[$row]['col2'] = $data[1];
// inc the row
$row++;
}
fclose($handle);
}
}
}
答案 2 :(得分：42)
虽然您可以轻松找到如何使用php处理文件上传的教程，并且有处理CSV的函数（手动），但我会发布一些代码，因为就在几天前我参与了一个项目，包括一些您可以使用的代码...
HTML：
<table width="600">
<form action="<?php echo $_SERVER["PHP_SELF"]; ?>" method="post" enctype="multipart/form-data">
<tr>
<td width="20%">Select file</td>
<td width="80%"><input type="file" name="file" id="file" /></td>
</tr>
<tr>
<td>Submit</td>
<td><input type="submit" name="submit" /></td>
</tr>
</form>
</table>
PHP：
if ( isset($_POST["submit"]) ) {
if ( isset($_FILES["file"])) {
//if there was an error uploading the file
if ($_FILES["file"]["error"] > 0) {
echo "Return Code: " . $_FILES["file"]["error"] . "<br />";
}
else {
//Print file details
echo "Upload: " . $_FILES["file"]["name"] . "<br />";
echo "Type: " . $_FILES["file"]["type"] . "<br />";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />";
//if file already exists
if (file_exists("upload/" . $_FILES["file"]["name"])) {
echo $_FILES["file"]["name"] . " already exists. ";
}
else {
//Store file in directory "upload" with the name of "uploaded_file.txt"
$storagename = "uploaded_file.txt";
move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $storagename);
echo "Stored in: " . "upload/" . $_FILES["file"]["name"] . "<br />";
}
}
} else {
echo "No file selected <br />";
}
}
我知道必须有一种更简单的方法，但我读取了CSV文件并将每个记录的单个单元格存储在二维数组中。
if ( isset($storagename) && $file = fopen( "upload/" . $storagename , r ) ) {
echo "File opened.<br />";
$firstline = fgets ($file, 4096 );
//Gets the number of fields, in CSV-files the names of the fields are mostly given in the first line
$num = strlen($firstline) - strlen(str_replace(";", "", $firstline));
//save the different fields of the firstline in an array called fields
$fields = array();
$fields = explode( ";", $firstline, ($num+1) );
$line = array();
$i = 0;
//CSV: one line is one record and the cells/fields are seperated by ";"
//so $dsatz is an two dimensional array saving the records like this: $dsatz[number of record][number of cell]
while ( $line[$i] = fgets ($file, 4096) ) {
$dsatz[$i] = array();
$dsatz[$i] = explode( ";", $line[$i], ($num+1) );
$i++;
}
echo "<table>";
echo "<tr>";
for ( $k = 0; $k != ($num+1); $k++ ) {
echo "<td>" . $fields[$k] . "</td>";
}
echo "</tr>";
foreach ($dsatz as $key => $number) {
//new table row for every record
echo "<tr>";
foreach ($number as $k => $content) {
//new table cell for every field of the record
echo "<td>" . $content . "</td>";
}
}
echo "</table>";
}
所以我希望这会有所帮助，它只是一小段代码而我没有测试过，因为我使用它略有不同。评论应该解释一切。
答案 3 :(得分：1)
你想要PHP手册的处理文件上传部分，你也可以看看fgetcsv（）和explode（）。
答案 4 :(得分：1)
你可以试试这个：
function doParseCSVFile($filesArray)
{
if ((file_exists($filesArray['frmUpload']['name'])) && (is_readable($filesArray['frmUpload']['name']))) {
$strFilePath = $filesArray['frmUpload']['tmp_name'];
$strFileHandle = fopen($strFilePath,"r");
$line_of_text = fgetcsv($strFileHandle,1024,",","'");
$line_of_text = fgetcsv($strFileHandle,1024,",","'");
do {
if ($line_of_text[0]) {
$strInsertSql = "INSERT INTO tbl_employee(employee_name, employee_code, employee_email, employee_designation, employee_number)VALUES('".addslashes($line_of_text[0])."', '".$line_of_text[1]."', '".addslashes($line_of_text[2])."', '".$line_of_text[3]."', '".$line_of_text[4]."')";
ExecuteQry($strInsertSql);
}
} while (($line_of_text = fgetcsv($strFileHandle,1024,",","'"))!== FALSE);
} else {
return FALSE;
}
}
答案 5 :(得分：0)
您好我觉得str_getcsv - 将CSV字符串解析为数组是您的最佳选择。
您需要将文件上传到服务器
使用str_getcsv解析文件。
运行数组并根据您的需要在您的网站中对齐。
答案 6 :(得分：0)
function doParseCSVFile($filesArray)
{
if ((file_exists($filesArray['frmUpload']['name'])) && (is_readable($filesArray['frmUpload']['name']))) {
$strFilePath = $filesArray['frmUpload']['tmp_name'];
$strFileHandle = fopen($strFilePath,"r");
$line_of_text = fgetcsv($strFileHandle,1024,",","'");
$line_of_text = fgetcsv($strFileHandle,1024,",","'");
do {
if ($line_of_text[0]) {
$strInsertSql = "INSERT INTO tbl_employee(employee_name, employee_code, employee_email, employee_designation, employee_number)VALUES('".addslashes($line_of_text[0])."', '".$line_of_text[1]."', '".addslashes($line_of_text[2])."', '".$line_of_text[3]."', '".$line_of_text[4]."')";
ExecuteQry($strInsertSql);
}
} while (($line_of_text = fgetcsv($strFileHandle,1024,",","'"))!== FALSE);
} else {
return FALSE;
}
}
答案 7 :(得分：0)
我在@Thomas Clowes 回答的帮助下创建了以下代码片段
$tmpName = $_FILES['csv']['tmp_name'];
$csv_data = array_map('str_getcsv', file($tmpName));
array_walk($csv_data , function(&$x) use ($csv_data) {
$x = array_combine($csv_data[0], $x);
});
// remove column header
array_shift($csv);
// Print Result Data
echo '<pre/>';
print_r($csv_data);
会得到如下结果
Array
(
[0] => Array
(
[make] => Audi
[model] => S4
[grade] =>
[chassis] => WAUZZZ8K9DA076529
[year] => 2012
[kms] => 127000
[color] => White
[doors] => 4
[cc] => 3000
[engineno] =>
[trans] => FAT
[fueltype] => P
[condition] => 4
[price] => 15753
)
)