Question

这是我的字符串：

width

我希望使用正则表达式替换字符串中的任何数字（整数或实数是否使用千位分隔符），并获取以下新字符串：

//Your imageView add tapGestureRecognizer event

  imageView.isUserInteractionEnabled = true
  let tapGestureRecognizer = UITapGestureRecognizer(target: self, action: #selector(tapAction))
  self.imageView.addGestureRecognizer(tapGestureRecognizer)

 @objc func tapAction(sender: UITapGestureRecognizer) {

      let touchPoint = sender.location(in: self.imageView)
      print(touchPoint)

      var z1 = touchPoint.x
      var z2 = touchPoint.y
      print("Before Alert Touched point (\(self.z1), \(self.z2)")

      //convert point into Percentage
      let z1per =  z1 * 100 / self.imageView.frame.size.width
      let z2per =  z2 * 100 / self.imageView.frame.size.height

      print("After Alert Touched point (\(self.z1per), \(self.z2per)")


  //whatever you want to add like button or image on tap action.

    let btn = UIButton(frame: CGRect(x: touchPoint.x - 15, y: touchPoint.y - 15, width: 30, height: 30))
    btn.layer.cornerRadius = 15
    btn image = UIImage(named: "marker.png") as UIImage?
    btn.setImage(image, for: .normal)
    self.imageView.addSubview(btn)
}

如何解决此问题？

Answer 1

您可以使用此正则表达式捕获数字，

\d+(?:[,.]\d+)*

在这里，\d+捕获一个具有一个或多个数字的数字，而(?:[,.]\d+)*可选地捕获多个以逗号或点分隔的数字，并用"$0"替换它们，其中{{1} }代表整个比赛。

Regex Demo

Java代码演示

$0

打印

String s = "\" \"hello\": 0, \"zulu\": 1,234, \"Bravo\": 987.456 \"";
System.out.println(s.replaceAll("\\d+(?:[,.]\\d+)*", "\"$0\""));

此外，您的预期结果似乎缺少输入字符串开头的双引号和空格，并且很可能是拼写错误。

RegEx fo替换字符串中的数字

1 个答案: