Question

我是Flask的新手，想知道是否可以使用相同的URL在html中显示表单并查询以显示某些东西

理想情况下，我希望发生以下结果。

如果要通过执行以下操作在138.10.2.1/sample中创建查询：

http://138.10.2.1:8000/sample?psi=1&lavr=1&dsc=1&ifsc=1&ics=1&eng=3&ol1=1&ol2=1&reso=1&educ=1&listen=1&time=1&probe=1&unders=1

它将显示：

*something in json format*

在网页中

否则，如果我直接讲：

http://138.10.2.1:8000/sample

它将引导我进入一个.html页面，其中包含一个表单以填充或允许用户附加文件以使用和上传，并以json格式显示转换后的文件。

这是我的代码

sample.py

from flask import Flask, flash, request, redirect, url_for, make_response, send_from_directory, render_template
import convert as ps

app = Flask(__name__)

@app.route("/sample", methods=["GET", "POST"])
def query_strings():

    #This is not working: if request.method == "POST":

        args1 = request.args["psi"]
        args2 = request.args["lavr"]
        args3 = request.args["dsc"]
        args4 = request.args["ifsc"]
        args5 = request.args["ics"]
        args6 = request.args["eng"]
        args7 = request.args["ol1"]
        args8 = request.args["ol2"]
        args9 = request.args["reso"]
        args10 = request.args["educ"]
        args11 = request.args["listen"]
        args12 = request.args["time"]
        args13 = request.args["probe"]
        args14 = request.args["unders"]

        args_list = [args1, args2, args3, args4, args5, args6, args7, args8,args9, args10, args11, args12, args13, args14]


        result = ps.execute(args_list)
        response = app.response_class(
            response=result,
            status=200,
            mimetype='application/json'
        )
        return response
    #This is my html form: return render_template("form.html")
if __name__ == '__main__':
   app.run(debug = True)

现在，我所能做的就是运行查询，但是如果我刚刚输入，我将被提示输入我声明的参数：

http://138.10.2.1:8000/sample

Answer 1

您可以检查参数的数量，如果长度为0，则返回HTML表单，如下所示：

    # if there are no arguments provided, show HTML form
    if len(request.args) == 0:
        return render_template("form.html")

此外，也不需要将每个参数存储为单独的变量，然后将它们组合成一个列表。 request.args已经是一个字典，因此您只需使用以下命令即可获取参数名称和值的列表：

list(request.args.keys()) # list of argument names eg. ['psi', 'lavr', 'dsc', 'ifsc'...]
list(request.args.values()) # list of argument values eg. [1, 1, 1, 1...]

您可以检查参数名称是否与所需集合匹配：

if set(argument_names) == {"psi","lavr","dsc","ifsc","ics","eng","ol1","ol2","reso","educ","listen","time","probe","unders"}:
        # return JSON

总体而言，您的代码可能如下所示：

from flask import Flask, request, render_template
import json

app = Flask(__name__)

@app.route("/sample", methods=["GET", "POST"])
def query_strings():
    # if there are no arguments provided, show HTML form
    if len(request.args) == 0:
        return render_template("form.html")

    argument_names = list(request.args.keys())

    # if the argument list is valid
    if set(argument_names) == {"psi","lavr","dsc","ifsc","ics","eng","ol1","ol2","reso","educ","listen","time","probe","unders"}:
        # return JSON
        response = app.response_class(
                response=json.dumps(request.args),
                status=200,
                mimetype='application/json'
        )
        return response

    return "Invalid arguments"

if __name__ == '__main__':
    app.run(debug = True)

这将：

如果不带参数加载form.html，请显示/sample
如果您使用有效的参数（例如/sample）加载/sample?psi=1&lavr=1&dsc=1&ifsc=1&ics=1&eng=3&ol1=1&ol2=1&reso=1&educ=1&listen=1&time=1&probe=1&unders=1，则将参数显示为JSON
在其他情况下显示“无效参数”

Answer 2

哦..我明白了..so如果不输入任何参数怎么显示.html？这将允许我在html表单中附加文件并创建到POST并获得相同的json结果

根据您对问题的评论和您发布的示例代码，我认为您可能正在寻找这样的东西：

@app.route("/sample", methods=["GET", "POST"])
def query_strings():
    args1 = request.args.get("psi")
    args2 = request.args.get("lavr")
    args3 = request.args.get("dsc")
    args4 = request.args.get("ifsc")
    args5 = request.args.get("ics")
    args6 = request.args.get("eng")
    args7 = request.args.get("ol1")
    args8 = request.args.get("ol2")
    args9 = request.args.get("reso")
    args10 = request.args.get("educ")
    args11 = request.args.get("listen")
    args12 = request.args.get("time")
    args13 = request.args.get("probe")
    args14 = request.args.get("unders")

    args_list = [
        args1, args2, args3, args4, args5, args6, args7, args8,
        args9, args10, args11, args12, args13, args14
    ]

    if not all(args_list):
        return render_template('form.html')
    else:
        result = ps.execute(args_list)
        response = app.response_class(
            response=result,
            status=200,
            mimetype='application/json'
        )
        return response

在这种情况下，如果您在GET请求中未提供任何参数，它将以html格式呈现模板。

也不要总是检查请求方法，我建议您看一下Flask的MethodView。使用它，您可以很好地将逻辑拆分为带有查询字符串中的参数的请求和使用json提交的表单： http://flask.pocoo.org/docs/1.0/api/#flask.views.MethodView

Answer 3

尝试此代码，希望对您有所帮助。默认情况下，它使用GET方法，因此它不起作用。当您单击提交按钮时，它将调用POST方法。

from flask import Flask, flash, request, redirect, url_for, make_response, send_from_directory, render_template
import convert as ps

app = Flask(__name__)

@app.route("/sample", methods=["GET", "POST"])
def query_strings():

    if request.method == "POST":

        args1 = request.args["psi"]
        args2 = request.args["lavr"]
        args3 = request.args["dsc"]
        args4 = request.args["ifsc"]
        args5 = request.args["ics"]
        args6 = request.args["eng"]
        args7 = request.args["ol1"]
        args8 = request.args["ol2"]
        args9 = request.args["reso"]
        args10 = request.args["educ"]
        args11 = request.args["listen"]
        args12 = request.args["time"]
        args13 = request.args["probe"]
        args14 = request.args["unders"]

        args_list = [args1, args2, args3, args4, args5, args6, args7, args8,args9, args10, args11, args12, args13, args14]


        result = ps.execute(args_list)
        response = app.response_class(
            response=result,
            status=200,
            mimetype='application/json'
        )
        # return response
        return render_template("form.html", response = response)
    return render_template("form.html")

    #This is my html form: return render_template("form.html")
if __name__ == '__main__':
   app.run(debug = True)

烧瓶：对单个网址使用[GET，POST]功能

3 个答案: