我正在尝试更改单击时每张图像的颜色,但是由于位置和z-index彼此重叠,因此无法正确选择它们。 您可以通过单击右上角的代码来检查代码的颜色是否改变...尝试了CSS的不同方法,而不是JavaScript ... JavaScript的新手。
body,div,p,h1,h2,h3,h4,h5,h6,span {
margin: 0;
}
div.nav {
height: 100px;
width: 100%;
padding: 20px 0;
background-color: #615d5d;
text-align: center;
}
.screens_wrap {
display: inline-block;
margin: 0 auto;
height: 100%;
position: relative;
}
.screen_inner {
position: relative;
height: 100%;
margin: 0 auto;
width: 150px;
}
.screen {
position: absolute;
width:100px;
height: 58px;
border: 3px solid #aeaeae;
}
/* transparent style -------------------------------------------------------------------*/
.nav .screen.screen1 {
bottom: 0;
left: 0;
z-index: 3;
background-color: #00ad63;
}
.nav a .screen.screen2 {
bottom: 15px;
left: 15px;
z-index: 2;
background-color: transparent;
}
.nav a .screen.screen2:hover{
background-color: #4f025a;
}
.nav .screen.screen3 {
bottom: 30px;
left: 30px;
z-index: 1;
background-color: transparent;
}
.nav .screen.screen3:hover{
background-color: #ffec36;
}
.nav .screen2:hover, .screen3:hover {
-webkit-animation-name: hover;
-webkit-animation-duration: 1s;
animation-name: hover;
animation-duration: 4s;
-webkit-animation-fill-mode: forwards;
opacity: 1;
width: 100px;
}
.nav.nav6 {
height: 200px;
}
.screen_inner a.screenanchors:first-child img {
position: absolute;
left: 0;
top: 0;
z-index: 1;
}
.screen_inner a.screenanchors:nth-child(2) img{
position: absolute;
left: 20px;
top: 20px;
z-index: 2;
}
.screen_inner a.screenanchors:nth-child(3) img{
position: absolute;
left: 40px;
top: 40px;
z-index: 3;
}
.screenanchors img {
overflow: hidden;
}
@keyframes spinning {
from {
transform: translateZ(-5em) rotateY(0deg);
}
to {
transform: translateZ(-5em) rotateY(180deg);
}
}
@keyframes skewing {
from {
transform: translateZ(-5em) skew(-3deg, -25deg);
}
to {
transform: translateZ(-5em) skew(-3deg, 0deg);
width: 100%;
height: 100px;
z-index: 9999999;
bottom: 0;
}
}
/* Standard syntax */
@keyframes hover {
0% {
margin-bottom:+10px;
bottom: unset;
}
100% {
margin-bottom:+10px;
bottom: unset;
}
}
<div class="nav nav6" style="margin-top: 25px;">
<div class="screens_wrap">
<div class="screen_inner">
<a href="javascript:void(0)" class="screenanchors"><img id="imgName" src="https://imageshack.com/i/plylrZh4p" onclick="changeSrc()" width="100px"></a>
<a href="javascript:void(0)" class="screenanchors"><img id="imgName1" src="https://imageshack.com/i/pljaZE0Gp" onclick="changeSrc1()" width="100px"></a>
<a href="javascript:void(0)" class="screenanchors"><img id="imgName2" src="https://imageshack.com/i/plm9slyTp" onclick="changeSrc2()" width="100px"></a>
</div>
</div>
</div>
<script>
function changeSrc(){
document.getElementById("imgName").src="https://imageshack.com/i/plm9slyTp";
document.getElementById("imgName1").src="https://imageshack.com/i/plylrZh4p";
document.getElementById("imgName2").src="https://imageshack.com/i/pljaZE0Gp";
}
function changeSrc1(){
document.getElementById("imgName").src="https://imageshack.com/i/pljaZE0Gp";
document.getElementById("imgName1").src="https://imageshack.com/i/plm9slyTp";
document.getElementById("imgName2").src="https://imageshack.com/i/plylrZh4p";
}
function changeSrc2(){
document.getElementById("imgName").src="https://imageshack.com/i/plylrZh4p";
document.getElementById("imgName1").src="https://imageshack.com/i/pljaZE0Gp";
document.getElementById("imgName2").src="https://imageshack.com/i/plm9slyTp";
}
</script>
它应该通过单击单个图像上的每个位置来工作,没有覆盖层会影响可点击的空间...
答案 0 :(得分:0)
为了帮助其他人,我使用区域映射解决了此问题...