Question

如何在循环外使用php变量

如何在循环外保存输出结果

此变量$ jsonrs

这是我想要循环外的结果

“ 1”“ 1.jpg”“ 2”“ 2.jpg”“ 3”“ 3.jpg”“ 4”“ 4.jpg”

$url =  'https://hentaifox.com/gallery/58769/';

$curl = curl_init();

curl_setopt($curl, CURLOPT_URL, $url);

curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, false);

curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);

$result = curl_exec($curl);

preg_match_all('!<img class="lazy no_image" data-src="(.*?)"!', $result, $manga_name);

$items = array();

foreach ($manga_name[1] as $key => $manganm) {


    $imag_manga = str_replace('t.jpg','.jpg',$manganm);

    $imagerep = 'https:'.$imag_manga;


    $filename = basename($imagerep);

    $imag_num = str_replace('.jpg','',$filename);

    $array_name = array($imag_num => $filename);

    $json1 = json_encode($imag_num);

    $json2 = json_encode($filename);

    $jsonrs = $json1.$json2;

    print_r($jsonrs);
}

Answer 1

您在$jsonrs中得到的最终结果有点不寻常，我（我假设）要对图像列表进行JSON编码，如果这样，则使用$items保留每个图像的列表，然后然后在循环后json_encode()将此列表...

foreach ($manga_name[1] as $key => $manganm) {
    $filename = basename($manganm);
    $imag_num = str_replace('t.jpg','',$filename);
    $items[$imag_num] = $filename;
}
echo json_encode($items);

会给你

{"1":"1t.jpg","2":"2t.jpg","3":"3t.jpg","4":"4t.jpg"}

如何在循环外保存输出结果

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