我无法使用libpq库为C ++中的数字类型绑定NULL值。 我使用了How to prepare statements and bind parameters in Postgresql for C++这个描述,效果很好。
但是我找不到如何为数字类型绑定NULL值。
pqxx::prepare::invocation& prep_dynamic(std::vector<std::string>& data, pqxx::prepare::invocation& inv)
{
std::vector<std::string>::const_iterator it;
for(it=data.begin();it!=data.end();it++)
{
inv((*it));
}
return inv;
}
try
{
pqxx::connection C("dbname = postgres user = postgres password=postgres hostaddr = 127.0.0.1 port = 5432");
if (C.is_open())
{
std::string dbname = C.dbname();
DIAG(DETAILED_INFO, "Opened database successfully:[%s]", dbname.c_str());
}
else
{
DIAG(DETAILED_INFO, "Can't open database!");
}
work W(C);
C.prepare("example", "insert into ipls_troubleticketerrorreport (CUSTOMER, NETWORK,SELECTABLEMONTH, ERRORCODE,ERRORMESSAGE, TTID ) " \
"values ($1, $2, to_date($3,'YYYY-MM-DD'), $4, $5, $6);");
pqxx::prepare::invocation w_invocation = W.prepared("example");
std::vector< std::pair<std::string,std::string> > sqlParameters2;
sqlParameters2.push_back(std::pair<std::string, std::string>("CUSTOMER", ""));
sqlParameters2.push_back(std::pair<std::string, std::string>("NETWORK", ""));
sqlParameters2.push_back(std::pair<std::string, std::string>("SELECTABLEMONTH", ""));
sqlParameters2.push_back(std::pair<std::string, std::string>("ERRORCODE",""));
sqlParameters2.push_back(std::pair<std::string, std::string>("ERRORMESSAGE", ""));
sqlParameters2.push_back(std::pair<std::string, std::string>("TTID",""));
for (int i = 0; i < sqlParameters2.size(); i++)
{
std::string value = "";
value = i_get(sqlParameters2[i].first.c_str());
sqlParameters2[i].second = value;
}
std::vector<std::string > vect;
for(int i=0; i<sqlParameters2.size();i++)
{
vect.push_back(sqlParameters2[i].second);
}
prep_dynamic(vect, w_invocation);
pqxx::result r = w_invocation.exec();
W.commit();
C.disconnect ();
}
catch(const std::exception &e)
{
DIAG(DETAILED_INFO, "exception occured.[%s]",e.what());
throw e;
}
答案 0 :(得分:0)
将 vect
的类型更改为 std::vector<std::optional<std::string>> vect;
并将 std::nullopt
设置为要分配为 null 的元素。就是这样。