Question

我目前正在实现一个计算自定义交叉熵损失的函数。该函数的定义如下图。

我的代码如下，

output = output.permute(0, 2, 3, 1)
target = target.permute(0, 2, 3, 1)

batch, height, width, channel = output.size()

total_loss = 0.
for b in range(batch): # for each batch
    o = output[b]
    t = target[b]
    loss = 0.
    for w in range(width):
        for h in range(height): # for every pixel([h,w]) in the image
            sid_t = t[h][w][0]
            sid_o_candi = o[h][w]
            part1 = 0. # to store the first sigma 
            part2 = 0. # to store the second sigma

            for k in range(0, sid_t):
                p = torch.sum(sid_o_candi[k:]) # to get Pk(w,h)
                part1 += torch.log(p + 1e-12).item()

            for k in range(sid_t, intervals):
                p = torch.sum(sid_o_candi[k:]) # to get Pk(w,h)
                part2 += torch.log(1-p + 1e-12).item()

            loss += part1 + part2

    loss /= width * height * (-1)
    total_loss += loss
total_loss /= batch
return torch.tensor(total_loss, dtype=torch.float32)

我想知道这些代码是否可以进行任何优化。

Answer 1

我不确定sid_t = t[h][w][0]是否对每个像素都相同。如果是这样，您可以摆脱所有for loop，这会提高计算损失的速度。

请勿使用.item()，因为它将返回丢失grad_fn轨道的Python值。这样就无法使用loss.backward()来计算渐变。

如果sid_t = t[h][w][0]不相同，请进行以下修改以帮助您摆脱至少1个for-loop：



batch, height, width, channel = output.size()

total_loss = 0.
for b in range(batch): # for each batch
    o = output[b]
    t = target[b]
    loss = 0.
    for w in range(width):
        for h in range(height): # for every pixel([h,w]) in the image
            sid_t = t[h][w][0]
            sid_o_candi = o[h][w]
            part1 = 0. # to store the first sigma 
            part2 = 0. # to store the second sigma

            sid1_cumsum = sid_o_candi[:sid_t].flip(dim=(0,)).cumsum(dim=0).flip(dims=(0,)) 
            part1 = torch.sum(torch.log(sid1_cumsum + 1e-12))

            sid2_cumsum = sid_o_candi[sid_t:intervals].flip(dim=(0,)).cumsum(dim=0).flip(dims=(0,)) 
            part2 = torch.sum(torch.log(1 - sid2_cumsum + 1e-12))

            loss += part1 + part2

    loss /= width * height * (-1)
    total_loss += loss
total_loss /= batch
return torch.tensor(total_loss, dtype=torch.float32)

工作原理：

x = torch.arange(10); 
print(x)

x_flip = x.flip(dims=(0,)); 
print(x_flip)

x_inverse_cumsum = x_flip.cumsum(dim=0).flip(dims=(0,))
print(x_inverse_cumsum)

# output
tensor([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])
tensor([9, 8, 7, 6, 5, 4, 3, 2, 1, 0])
tensor([45, 45, 44, 42, 39, 35, 30, 24, 17,  9])

希望有帮助。

代码优化：Torch.Tensor中的计算

1 个答案: