因此,我正在制作一个2D角色控制器,如果按住鼠标(长按),玩家可以设置他要发射弹丸的方向,而当发射弹丸并与物体碰撞时,玩家可以设置该方向可以单击一次(或者最好单击两次)以将角色的位置替换为弹丸的位置。我正在尝试使用Input.onMouseButton和Input.onMouseButtonDown来做,但是我真的不知道。谢谢大家对我有帮助!
答案 0 :(得分:0)
据我从文档和论坛中得知,您将需要使用Input.GetMouseButtonDown
进行检查,以及自第一次按下以来经过的时间,例如so。
答案 1 :(得分:0)
除了获取带有按钮的GetMouseButtonDown(int)之外,您还要跟踪记住检查按钮在哪个阶段。
答案 2 :(得分:0)
对于长按,您只需要测量自第一次单击以来经过的时间。这是一个示例:
using System.Collections;
using System.Collections.Generic;
using UnityEngine;
using UnityEngine.Events;
public class LongClick : MonoBehaviour
{
public float ClickDuration = 2;
public UnityEvent OnLongClick;
bool clicking = false;
float totalDownTime = 0;
// Update is called once per frame
void Update()
{
// Detect the first click
if (Input.GetMouseButtonDown(0))
{
totalDownTime = 0;
clicking = true;
}
// If a first click detected, and still clicking,
// measure the total click time, and fire an event
// if we exceed the duration specified
if (clicking && Input.GetMouseButton(0))
{
totalDownTime += Time.deltaTime;
if (totalDownTime >= ClickDuration)
{
Debug.Log("Long click");
clicking = false;
OnLongClick.Invoke();
}
}
// If a first click detected, and we release before the
// duraction, do nothing, just cancel the click
if (clicking && Input.GetMouseButtonUp(0))
{
clicking = false;
}
}
}
对于双击,您只需检查是否在指定的(短)间隔内再次单击:
using System.Collections;
using System.Collections.Generic;
using UnityEngine;
using UnityEngine.Events;
public class DoubleClick : MonoBehaviour
{
public float DoubleClickInterval = 0.5f;
public UnityEvent OnDoubleClick;
float secondClickTimeout = -1;
void Update()
{
if (Input.GetMouseButtonDown(0))
{
if (secondClickTimeout < 0)
{
// This is the first click, calculate the timeout
secondClickTimeout = Time.time + DoubleClickInterval;
}
else
{
// This is the second click, is it within the interval
if (Time.time < secondClickTimeout)
{
Debug.Log("Double click!");
// Invoke the event
OnDoubleClick.Invoke();
// Reset the timeout
secondClickTimeout = -1;
}
}
}
// If we wait too long for a second click, just cancel the double click
if (secondClickTimeout > 0 && Time.time >= secondClickTimeout)
{
secondClickTimeout = -1;
}
}
}