Question

我有下面的数组，我要做的是根据另一个数组中的值从下面的数组中删除属性名称，即键和值。

选项如下所示，仅使用Keep数组中的值创建一个新数组，或从原始数组中删除“ keep”数组中未列出的值。

var Keep=["ItemID","ItemNumber","OptionNo","Quantity","Price","Description","StockStatus","Url"]; 
var originalarray=[
      {
        "ItemID": 1,
        "ItemNumber": "611741",
        "OptionNo": "22",
        "SizeDescription": "3-6 Mths",
        "Price": "14.00",
        "Quantity": 1,
        "StockStatus": "instock",
        "StockMessage": "In Stock",
        "WarrantyItem": null,
        "Description": "Coral/Blue Embellished Two In One Dress (3mths-7yrs)",
        "Url": "/g82272s2",
        "FulfilmentType": ""
      },
      {
        "ItemID": 2,
        "ItemNumber": "912767",
        "OptionNo": "13",
        "SizeDescription": "11 EU 29",
        "Price": "16.00",
        "Quantity": 1,
        "StockStatus": "instock",
        "StockMessage": "In Stock",
        "WarrantyItem": null,
        "Description": "Silver Buckle Corkbed Sandals (Younger)",
        "Url": "/g82272s2",
        "CustomItemFields": [],
        "FulfilmentType": ""
      }
    ]

我试图创建新数组，但该数组未嵌套，因此对于相同的键，我有多个条目，其值如下：

["ItemID:1", 
"ItemNumber:611741", 
"OptionNo:22", 
"Price:14.00", 
"Quantity:1", 
"StockStatus:instock", 
"Description:Coral/Blue Embellished Two In One Dress (3mths-7yrs)", "Url:/g82272s2", 
"ItemCategory:Dresses", 
"ItemID:2",
 "ItemNumber:912767", 
"OptionNo:13", 
"Price:16.00",
 "Quantity:1", 
"StockStatus:instock", 
"Description:Silver Buckle Corkbed Sandals (Younger)", 
"Url:/g82272s2", 
"ItemCategory:Sandals"]

I want the result array to be like this 

[{"ItemID:1", 
"ItemNumber:611741", 
"OptionNo:22", 
"Price:14.00", 
"Quantity:1", 
"StockStatus:instock", 
"Description:Coral/Blue Embellished Two In One Dress (3mths-7yrs)", "Url:/g82272s2", 
"ItemCategory:Dresses"}, 
{"ItemID:2",
 "ItemNumber:912767", 
"OptionNo:13", 
"Price:16.00",
 "Quantity:1", 
"StockStatus:instock", 
"Description:Silver Buckle Corkbed Sandals (Younger)", 
"Url:/g82272s2", 
"ItemCategory:Sandals"}]

这是我的代码：

var keep=["ItemID", "ItemNumber", "OptionNo", "Quantity", "Price", "Description", "ItemCategory", "StockStatus", "Url"],z={}; z=new Array(); y.forEach(function(arrays){
  // 4 arrays in a
  var x=Object.keys(arrays);
  var k=Object.values(arrays); 
  //console.log(x);
  //console.log(y);
for(var i = 0; i < x.length; i++) {
  //console.log(x[i]);
 keep.forEach(function(item,index,array){
      if(item==x[i]){
          //z.push(x[i]+":"+y[i]);
         z.push(x[i]+":"+k[i]);
          return z;
                    }
  })
 }
  })

希望您能提供帮助。

谢谢。

Answer 1

更新：
因此，这里的lodash版本可能也更易于阅读：

const keep = (k, l) => _.map(l, o => _.pick(o, k))

const keepThese = ["ItemID", "ItemNumber", "OptionNo", "Quantity", "Price", "Description", "StockStatus", "Url"]
const orig = [{"ItemID": 1, "ItemNumber": "611741", "OptionNo": "22", "SizeDescription": "3-6 Mths", "Price": "14.00", "Quantity": 1, "StockStatus": "instock", "StockMessage": "In Stock", "WarrantyItem": null, "Description": "Coral/Blue Embellished Two In One Dress (3mths-7yrs)", "Url": "/g82272s2", "FulfilmentType": ""},
  {"ItemID": 2, "ItemNumber": "912767", "OptionNo": "13", "SizeDescription": "11 EU 29", "Price": "16.00", "Quantity": 1, "StockStatus": "instock", "StockMessage": "In Stock", "WarrantyItem": null, "Description": "Silver Buckle Corkbed Sandals (Younger)", "Url": "/g82272s2", "CustomItemFields": [], "FulfilmentType": ""}]
console.log(keep(keepThese, orig))

<script src="//cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>

文档： _.map()，_.pick()

例如，尽管使用lodash可能会有更优雅的方式，但是下面的keep函数将做到这一点。

const keep = (k, l) => l.map(o => Object.entries(o).reduce((r, [n, v]) => 
  k.includes(n) ? (r[n] = v, r) : r, {}))

const keepThese = ["ItemID", "ItemNumber", "OptionNo", "Quantity", "Price", "Description", "StockStatus", "Url"]
const orig = [{"ItemID": 1, "ItemNumber": "611741", "OptionNo": "22", "SizeDescription": "3-6 Mths", "Price": "14.00", "Quantity": 1, "StockStatus": "instock", "StockMessage": "In Stock", "WarrantyItem": null, "Description": "Coral/Blue Embellished Two In One Dress (3mths-7yrs)", "Url": "/g82272s2", "FulfilmentType": ""},
  {"ItemID": 2, "ItemNumber": "912767", "OptionNo": "13", "SizeDescription": "11 EU 29", "Price": "16.00", "Quantity": 1, "StockStatus": "instock", "StockMessage": "In Stock", "WarrantyItem": null, "Description": "Silver Buckle Corkbed Sandals (Younger)", "Url": "/g82272s2", "CustomItemFields": [], "FulfilmentType": ""}]
console.log(keep(keepThese, orig))

说明： .map()的输入 Object.entries() 从Object开始.reduce()到{}。
因此(r, [n, v]) => k.includes(n) ? (r[n] = v, r) : r为数组中每个对象中的每个属性运行。如果属性数组保留.includes()为当前属性的名称，请将相应的属性和值添加到r。否则，请勿触摸r。重复下一个属性，最后在结果数组中添加r。

Answer 2

我建议您研究map()和filter()甚至是find()的用法。

请参阅有关使用Map和Filter或Find的文档。

有了它们，您可以对数组中的对象执行各种验证和转换。

要排除带有对象值的键，您将需要：

delete myObject.regex;
// or,
delete myObject['regex'];
// or,
var prop = "regex";
delete myObject[prop];

遍历数组中的嵌套对象并删除属性名称和值

2 个答案: