Question

这是我的complex (atleast i think it is complex)条件，可以根据比赛时间表查找竞争对手并与事件相关。

现在我与HTBTM表有events_competitors个关系，其中多个事件有多个竞争对手用户条目。

在这里，我使用joins条件加入并获得events competitors与is_black相关的工作正常，但我还想为is_adult应用其他条件（检查黑带）和'EventCompetitor.is_black' => 0, 'EventCompetitor.is_adult' => 0,（检查成年人）

$matchdivisions = $this->Competitor->find("all" , 

                               array(

                                'conditions' => 

                                   array(

                   'Competitor.status' => 1, 
                   'Competitor.payment_completed' => 1,
                   'Competitor.weightgroup_id' => $current_matchsc['Matchschedule']['weightgroup_id'],
                   'Competitor.rank_id' => $current_matchsc['Matchschedule']['rank_id'],
                   'Competitor.degree_id' => $current_matchsc['Matchschedule']['degree_id'],
                   'Competitor.gender' => $current_matchsc['Matchschedule']['gender'],

                                    ),

                                    'joins' => 

                                      array(

                                        array(

                                           'table' => 'event_competitors',
                                           'alias' => 'EventCompetitor',
                                           'type' => 'left',
                                           'conditions'=> array(

                                                "AND" =>array(

                        'EventCompetitor.event_id = '.$current_matchsc['Event']['id'],
                        'EventCompetitor.is_black' => 0,
                        'EventCompetitor.is_adult' => 0,

                                                      )
                                                 ),
                                           )
                                     ),

                                    'group' => 'Competitor.id'

                                  )

                             );

在这里，我只想要那些同时具有两个条件（is_black / is_adult）0的竞争对手，意味着不符合条件，但不适用相同的竞争对手，这会导致错误的竞争对手结果。

以下是我的整个查找条件：

JOIN

任何想法，如何将这些内容应用到Competitor条件中，以便将其应用到结果中。

谢谢！

以下是您的参考的SQL Dump：

选择id。Competitor，first_name。Competitor，last_name。Competitor，parent_name。{{1} }，Competitor。gender，Competitor。date_of_birth，Competitor。email_address，Competitor。weight， Competitor。weightgroup_id，Competitor。height，Competitor。rank_id，Competitor。degree_id，{{ 1}}。Competitor，photo。Competitor，school_id。Competitor，years_of_experience。Competitor，{{1} }。age，Competitor。tournament_id，Competitor。total_registration_fees，Competitor。address1，Competitor。 address2，Competitor。city，Competitor。zip_code，Competitor。country_id，Competitor。{{ 1}}，state_id。Competitor，phone_number。Competitor，mobile_number。Competitor，payment_mode。{{1} }，Competitor。email_sent，Competitor。payment_completed，Competitor。status，Competitor。created， Competitor。modified，Rank。id，Rank。name，Rank。status，{{ 1}}。Rank，created。Rank，modified。Tournament，id。Tournament，{{1} }。tournament_name，Tournament。tournament_type，Tournament。tournament_date，Tournament。venue_name，Tournament。 address1，Tournament。address2，Tournament。city，Tournament。zip_code，Tournament。{{ 1}}，country_id。Tournament，state_id。Tournament，created。Tournament，modified。{{1} }，Country。id，Country。name，Country。status，Country。created， Country。modified，State。id，State。country_id，State。name，{{ 1}}。State，short_name。State，status。State，created。State，{{1} }。modified，Degree。id，Degree。rank_id，Degree。name，Degree。 status，Degree。created，School。id，School。name，School。{{ 1}}，address1。School，{{ 1}}。address2，School。city，School。zip_code，School。country_id，{{1} }。School，state_id。School，phone_number。School，owner_name。School，establishment_date。 School，total_competitors。School，status。School，created。School，modified。{{ 1}}，Transaction。id，Transaction。competitor_id，Transaction。noncompetitor_id，Transaction。{{1} }，created。Transaction，modified。Transaction，mc_gross。Transaction，address_status。Transaction， payer_id。Transaction，address_street。Transaction，payment_date。Transaction，payment_status。Transaction，{{ 1}}。address_zip，Transaction。first_name，Transaction。address_country_code，Transaction。address_name，{{1} }。Transaction，custom。Transaction，payer_status。Transaction，address_country。Transaction，address_city。 Transaction，payer_email。Transaction，verify_sign。Transaction，txn_id。Transaction，payment_type。{{ 1}}，Transaction。last_name，Transaction。address_state，Transaction。receiver_email FROM Transaction AS {{1} }左JOIN event_competitors AS item_name ON（Transaction。mc_currency = 3 AND Transaction。item_number = 0 AND Transaction。{{1} } = 0）LEFT JOIN residence_country AS Transaction ON（transaction_subject。Transaction = payment_gross。Transaction）LEFT JOIN shipping AS Transaction ON（test_ipn。Transaction = pending_reason。competitors）LEFT JOIN Competitor AS EventCompetitor ON（{{1} } {。{1}} = EventCompetitor。event_id）LEFT JOIN EventCompetitor AS is_black ON（EventCompetitor。is_adult = {{ 1}}。ranks）LEFT JOIN Rank AS Competitor ON（rank_id。Rank = id。tournaments）LEFT加入Tournament AS Competitor ON（tournament_id。Tournament = id。countries）LEFT JOIN Country AS Competitor ON（country_id。Country = id。states）WHERE State。Competitor = 1 AND {{1 } {。{1}} = 1 AND state_id。State = 13 AND id。degrees = 11 AND Degree。Competitor ='0'和degree_id。Degree ='女'GROUP BY id。schools

以下是来自ref：

的查询的左连接条件

School

Answer 1

您应该使用可包含的行为。更多信息：http://book.cakephp.org/view/1323/Containable

将其添加到竞争对手的型号中。


var $actsAs = array('Containable');

在竞争对手模型中更新您的模型关系，以包含is_black和is_adult条件：

    
var $hasAndBelongsToMany = array(
                'Competitor' => array(
                    'className' => 'Competitor',
                    'joinTable' => 'event_competitors',
                    'alias' => 'EventCompetitor',
                    'conditions' => array(
                        'EventCompetitor.is_black' => 0,
                        'EventCompetitor.is_adult' => 0
                    )
                 )
            );

3）要注入事件id，请将contains数组传递给find操作：

$contain = array(
    'EventCompetitor' => array(
        'conditions' => array('EventCompetitor.event_id' =>  $current_matchsc['Event']['id'])
    )
);
$matchdivisions = $this->Competitor->find("all" , 
    array(
        'contain' => $contain,
        'conditions' => array(
            'Competitor.status' => 1, 
             'Competitor.payment_completed' => 1,
            'Competitor.weightgroup_id' => $current_matchsc['Matchschedule']['weightgroup_id'],
            'Competitor.rank_id' => $current_matchsc['Matchschedule']['rank_id'],
            'Competitor.degree_id' => $current_matchsc['Matchschedule']['degree_id'],
            'Competitor.gender' => $current_matchsc['Matchschedule']['gender']
        )
    )
);

如果关系并不总是需要is_black和is_adult，那么您可能希望从模型中移除这些条件，并根据需要通过find操作的contains参数传递它们。

CakePHP多个JOIN findAll条件问题

1 个答案: