Question

我是C＃的新手，所以如果我的问题没有意义，请抱歉。在我的应用程序中，C＃DLL需要打开命令提示符，为Linux系统提供一个plink命令来获取系统相关的字符串并将该字符串设置为环境变量。我可以在创建C＃控制台应用程序时执行此操作，使用plink命令在命令提示符下获取字符串，并使用C＃中的进程类设置环境变量以打开plink作为单独的控制台进程。但是，在C＃DLL中我必须打开cmd.exe 1st然后给出这个命令，我不知道如何实现？我尝试打开cmd.exe作为进程，然后尝试将输入和输出重定向到进程并给出命令并获取字符串回复，但没有运气。请让我知道任何其他解决方法。

感谢您的回答， Ashutosh说

Answer 1

感谢您的快速回复。编写代码序列是我的错误。现在很少有变化，代码就像魅力一样。这是代码，

    string strOutput;
    //Starting Information for process like its path, use system shell i.e. control process by system etc.
    ProcessStartInfo psi = new ProcessStartInfo(@"C:\WINDOWS\system32\cmd.exe");
    // its states that system shell will not be used to control the process instead program will handle the process
    psi.UseShellExecute = false;
    psi.ErrorDialog = false;
    // Do not show command prompt window separately
    psi.CreateNoWindow = true;
    psi.WindowStyle = ProcessWindowStyle.Hidden;
    //redirect all standard inout to program
    psi.RedirectStandardError = true;
    psi.RedirectStandardInput = true;
    psi.RedirectStandardOutput = true;
    //create the process with above infor and start it
    Process plinkProcess = new Process();
    plinkProcess.StartInfo = psi;
    plinkProcess.Start();
    //link the streams to standard inout of process
    StreamWriter inputWriter = plinkProcess.StandardInput;
    StreamReader outputReader = plinkProcess.StandardOutput;
    StreamReader errorReader = plinkProcess.StandardError;
    //send command to cmd prompt and wait for command to execute with thread sleep
    inputWriter.WriteLine("C:\\PLINK -ssh root@susehost -pw opensuselinux echo $SHELL\r\n");
    Thread.Sleep(2000);
    // flush the input stream before sending exit command to end process for any unwanted characters
    inputWriter.Flush();
    inputWriter.WriteLine("exit\r\n");
    // read till end the stream into string
    strOutput = outputReader.ReadToEnd();
    //remove the part of string which is not needed
    int val = strOutput.IndexOf("-type\r\n");
    strOutput = strOutput.Substring(val + 7);
    val = strOutput.IndexOf("\r\n");
    strOutput = strOutput.Substring(0, val);
    MessageBox.Show(strOutput);

到目前为止，我解释了代码...，非常感谢

如何在C＃GUI应用程序中的命令提示符下发送命令和接收数据

1 个答案: