Question

我有两个表：

Receive_Amount_Details用于从施工现场所有者处贷记金额，并且
SitewiseEmployee是借方借方支付给劳工的款项。

对于两个表中都存在的每个Date，我想：

将Amount_Received中的所有Receive_Amount_Details总计为Total_Receive_Amount_from_siteowner，并且
将Amount中的所有SitewiseEmployee都作为Total_Amount_Payed_to_Labour 输出表上的列。

两个表都具有Date列，但我希望输出中有一个Date列。

如果未收到任何单日金额并支付了人工，则应将其显示在输出表中，并且如果收到任何单日金额但未支付劳力的工资，则也应将其显示在输出表中

CREATE TABLE `Receive_Amount_Details` (
    `Id` int(10) NOT NULL AUTO_INCREMENT,
    `SiteId` int(5) NOT NULL,
    `Amount_Received` int(10) NOT NULL,
    `Date` date NOT NULL,
    PRIMARY KEY (`Id`),
    KEY `SiteId` (`SiteId`),
    CONSTRAINT `Receive_Amount_Details_ibfk_1` FOREIGN KEY (`SiteId`) 
        REFERENCES `SiteList` (`Id`)
) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=latin1

和

CREATE TABLE `SitewiseEmployee` (
    `Id` int(10) NOT NULL AUTO_INCREMENT,
    `SiteId` int(5) NOT NULL,
    `EmployeeId` int(10) NOT NULL,
    `Amount` varchar(10) DEFAULT NULL,
    `Date` date NOT NULL,
    PRIMARY KEY (`Id`),
    KEY `SiteId` (`SiteId`),
    KEY `EmployeeId` (`EmployeeId`),
    CONSTRAINT `SitewiseEmployee_ibfk_1` FOREIGN KEY (`SiteId`) 
        REFERENCES `SiteList` (`Id`),
    CONSTRAINT `SitewiseEmployee_ibfk_2` FOREIGN KEY (`EmployeeId`)
        REFERENCES `Employee` (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=latin1

Answer 1

假设一个表中的日期可能不存在于另一个表中，反之亦然，那么您将需要执行完全外部联接。 MySql没有这种联接类型，但是可以通过并集来实现它：

select    `Date`,
          sum(Amount_Received) as Sum_Amount_Received,
          sum(Amount) as Sum_Amount
from      (
                select `Date`, Amount_Received, 0 as Amount
                from   Receive_Amount_Details
                union
                select `Date`, 0, Amount
                from   SitewiseEmployee
          ) as dates
group by  `Date`;

如何在一个输出中从两个表中获得两个和？

1 个答案: