使用include（）

Question

因此，我正在使用将标签用作搜索过滤器的应用程序中工作。但是，使用两个标签时无法得到结果。例如，名为CoffeShop的商店有两个标签“ Coffee”和“ Cookies”。传递其中一个时，它将返回CoffeShop，但传递两个标签时，则不返回任何内容。

我尝试使用loadash和其他一些东西，但到目前为止都没有起作用。

let array = [
  {
    "name": "CoffeShop",
    "tag":[
      "Coffee",
      "Cookies",
    ],
  },
   {
    "name": "TeaShop",
    "tag":[
      "Tea",
    ],
  },
   {
    "name": "IceCreamShop",
    "tag": [
      "Ice Cream",
    ]
  },
]



let tags = ['Coffee', 'Cookies']   
result = array.filter(item => item.tag.some(t =>  t.includes(tags)))
console.log(result)

实际结果只能给我一家CoffeShop的商店，但我什么也没得到

Answer 1

仅反向包含应该是数组。include（项目）

let array = [
  {
    "name": "CoffeShop",
    "tag":[
      "Coffee",
      "Cookies",
    ],
  },
   {
    "name": "TeaShop",
    "tag":[
      "Tea",
    ],
  },
   {
    "name": "IceCreamShop",
    "tag": [
      "Ice Cream",
    ]
  },
]



let tags = ['Coffee', 'Cookies']  

result = array.filter(item => item.tag.some(t =>  tags.includes(t)))

console.log(result)

Answer 2

let array = [
  {
    "name": "CoffeShop",
    "tag":[
      "Coffee",
      "Cookies",
    ],
  },
   {
    "name": "TeaShop",
    "tag":[
      "Tea",
    ],
  },
   {
    "name": "IceCreamShop",
    "tag": [
      "Ice Cream",
    ]
  },
]
const _strip = str => str.replace(/\s/g, '')
const _minimize = arr => arr.map(t => _strip(t.toLowerCase()))

const getShopWithTags = (shops = [], tags = []) => {
  tags = _minimize(tags)
  return array.filter(({tag}) => tags.includes(..._minimize(tag)))
}

let tags = ['Coffee', 'Cookies']  
let result = getShopWithTags(array, tags)
console.log(result)

tags = ['Coffee', 'Cookies', 'Ice Cream']
result = getShopWithTags(array, tags)
console.log(result)

let array = [
  {
    "name": "CoffeShop",
    "tag":[
      "Coffee",
      "Cookies",
    ],
  },
   {
    "name": "TeaShop",
    "tag":[
      "Tea",
    ],
  },
   {
    "name": "IceCreamShop",
    "tag": [
      "Ice Cream",
    ]
  },
]

let tags = ['Coffee', 'Cookies']  
let result = array.filter(({tag}) => tags.includes(...tag))
console.log(result)

tags = ['Coffee', 'Cookies', 'Ice Cream']
result = array.filter(({tag}) => tags.includes(...tag))
console.log(result)

Answer 3

您需要像tags.includes(t)那样做。在您的代码中，您刚刚反转了包含，它应该是Array.include(item)

let array = [
  {
    "name": "CoffeShop",
    "tag":[
      "Coffee",
      "Cookies",
    ],
  },
   {
    "name": "TeaShop",
    "tag":[
      "Tea",
    ],
  },
   {
    "name": "IceCreamShop",
    "tag": [
      "Ice Cream",
    ]
  },
]



let tags = ['Coffee', 'Cookies']   
result = array.filter(item => item.tag.some(t =>  tags.includes(t)))
console.log(result)

Answer 4

问题是Array.prototype.includes()会在标签内寻找一个数组，而不会自动为您检查数组中的所有值。您可以执行以下操作：

result = array.filter(item => tags.every(tag => item.tag.includes(tag)));

Answer 5

假设您要查找包含 all 标签的条目，则必须检查cron.yaml是否包含array[n].tags中的所有项目：

tags