Question

这是我的桌子T1

  dat_dt      credit     debit
 --------     ------     -----
22-02-2019      10         5
25-02-2019      30         60
10-03-2019      50         40
13-03-2019      100        10

我想生成以下输出

max_date    cr_sum    progressive credit  dr_sum progressive debit 
--------    ------    ------------------  ------  -----------------
25-02-2019    40            40              65           65
13-03-2019    150           190             50           115

我想计算每个月的贷方和借方之和，累进贷方是在该月的贷方总和加上上个月的累进贷方的列。对于累进借记也是如此。 max_date是每个月的最大日期。除了使用循环之外，是否有任何简单的方法来获取此输出？

Answer 1

您可以在下面尝试-

select max(dat_date) as max_date,sum(credit) as cr_sum,
       sum(credit) over(order by EXTRACT(month FROM dat_date),EXTRACT(year FROM dat_date)) as progressive_credit,
       sum(debit) as dr_sum,
       sum(debit) over(order by EXTRACT(month FROM dat_date),EXTRACT(year FROM dat_date)) as progressive_debit
group by EXTRACT(month FROM dat_date),EXTRACT(year FROM dat_date)

Answer 2

您似乎想要一个累加的总和，但按月汇总：

select max(dat_dt) as dat_dt,
       sum(credit) as credit,
       sum(sum(credit)) over (order by min(dat_dt)) as running_credit,
       sum(debit) as debit,
       sum(sum(debit)) over (order by min(dat_dt)) as running_debit
from t1
group by to_char(dat_dt, 'YYYY-MM')
order by min(dat_dt);

Here是db <>小提琴。

Answer 3

您可以使用以下查询

with t1(  dat_dt, credit, debit) as
(
 select date'2019-02-22',10,  5 from dual union all
 select date'2019-02-25',30, 60 from dual union all
 select date'2019-03-10',50, 40 from dual union all
 select date'2019-03-13',100,10 from dual    
)
select max(dat_dt) as "max date",
       sum(credit) as "cr sum",
       sum(sum(credit)) over ( order by to_char(dat_dt,'yyyymm') ) as "progressive credit", 
       sum(debit) as "dr sum",
       sum(sum(debit))  over ( order by to_char(dat_dt,'yyyymm') ) as "progressive debit"
  from t1
 group by to_char(dat_dt,'yyyymm')
 order by to_char(dat_dt,'yyyymm');

按年月组合汇总。

Demo

sql查询以计算总和并添加前几行的总和

3 个答案: