Question

我想计算每一行的列数据框中字符串列表中现有单词的数量。

代码：

   list_1 = ['Apple', 'Mango' ,'Orange', 'pr[éeêè]t[s]?' ]
   list_2 = ['weather', 'r[ea]d' ,'p[wr]iority', 'pr[éeêè]t[s]?' ]
   list_3 = ['n[eéè]d','snow[s]?', 'pr[éeêè]t[s]?' ]
   dict = {"s1":['Column_1', list_1],
                    "s2": ['Column_1', list_3],
                    "s3": ['Column_2', list_2],
                    "s4": ['Column_3', list_3],
                    "s5": ['Column_2','Column_3',list_1],}

  for elt in list(dict.keys()):
    if len(dict[elt])<=2:
        d = Counter(re.findall(r'|'.join(dict[elt][1]).lower(), df[dict[elt][0]].str.lower()))
        df[elt] = sum(d.values()) 
    elif len(dict[elt])>2:
        aa = Counter(re.findall(r'|'.join(dict[elt][2]).lower(), df[dict[elt][0]].str.lower()))
        bb = Counter(re.findall(r'|'.join(dict[elt][2]).lower(), df[dict[elt][1]].str.lower()))
        b = sum(bb.values()) 
        a = sum(aa.values()) 
        d = a +b 
        df[elt] = d

数据示例：

     d = {'Column_1': ['mango pret Orange No manner', ' préts  No scan'],  'Column_2': ['read priority No', 'This is a priority'],'Column_3': ['No add', 'yep']}
     df = pd.DataFrame(data=d)

     d2 = {'s1': [3, 1], 's3':[2,1]}
     df2 = pd.DataFrame(data=d2)

但是我遇到了这个错误... TypeError：预期的字符串或类似字节的对象

Answer 1

这对我有用（python 3.6.8版）：

d = {'Column_1': ['mango pret Orange No manner', ' préts  No scan'],  'Column_2': ['read priority No', 'This is a priority'],'Column_3': ['No add', 'yep']}
df = pd.DataFrame(data=d)

d2 = {'s1': [3, 1], 's3':[2,1]}
df2 = pd.DataFrame(data=d2)

list_1 = ['Apple', 'Mango' ,'Orange', 'pr[éeêè]t[s]?' ]
list_2 = ['weather', 'r[ea]d' ,'p[wr]iority', 'pr[éeêè]t[s]?' ]
list_3 = ['n[eéè]d','snow[s]?', 'pr[éeêè]t[s]?' ]
dic = {"s1":['Column_1', list_1],
            "s2": ['Column_1', list_3],
            "s3": ['Column_2', list_2],
            "s4": ['Column_3', list_3],
            "s5": ['Column_2','Column_3',list_1],}

for elt in list(dic.keys()):
    if len(dic[elt])<=2:
        d = Counter(re.findall(r'|'.join(dic[elt][1]).lower(), str(df[dic[elt][0]].str.lower())))
        df[elt] = sum(d.values()) 
    elif len(dic[elt])>2:
        aa = Counter(re.findall(r'|'.join(dic[elt][2]).lower(), str(df[dic[elt][0]].str.lower())))
        bb = Counter(re.findall(r'|'.join(dic[elt][2]).lower(), str(df[dic[elt][1]].str.lower())))
        b = sum(bb.values()) 
        a = sum(aa.values()) 
        d = a +b 
        df[elt] = d

TypeError：预期的字符串或类似字节的对象python重新打包

1 个答案: