Question

我有一个项目要编写一个对矩阵执行数学运算的代码。用户以字符串形式输入一个矩阵，然后输入一个运算符，如果它是+或-或*或/，则用户必须输入另一个矩阵... 因此，我想创建一个执行每个操作的函数，并从ADD函数开始，但是在主函数中调用它时出现错误。输入矩阵的示例：[3 4 9; 2 5 8; 1 2 50] 注意：不得打印出多余的空格或分号。

#include <iostream>
#include <string>
#include <cstring>
#include <sstream>
#include <cstdlib>
#include <algorithm>

using namespace std;
string ADD (float matrix1,float matrix2,int arraySize);
int main()
{
  string s1; //first matrix
  char op; //operator
  string s2;//second matrix
  int y; //for power operation
  int n = 0; //number of rows of first matrix
  int m = 0; //number of columns of first matrix
  int o = 0; //number of rows of second matrix
  int p = 0;//number of columns of second matrix

  getline(cin, s1);

  for (int i = 0; i < s1.size(); i++)
  {

  if (s1[i] == ';') n++;

  }
  for (int j = 0; j < s1.size(); j++)
  {
      if (s1[j] == ' ') m++;
  }
 n = n+1;
 m = (m/n)+1;

  s1.erase(0, 1); //to remove  first bracket

  for (int z = 0; z < s1.size(); z++) //to replace characters with a space
  {
       if (s1[z] == ';' || s1[z] == ']') s1[z] = ' ';
  }
    string token1;
    float matrix1 [n*m];
    for (int x = 0; x < n*m; x++)
   {
    token1 = s1.substr(0, s1.find(" "));
    float v = atof(token1.c_str());
    matrix1 [x] = v;
    s1.erase(0, s1.find(" ")+1);
   }
   cout <<"Please Enter An Operator From The Following List: '+ - * ^ T D I /'" <<endl;
   cin >> op;
   if (op == '+' || op == '-' || op == '*' || op == '/')
   {
       cin.ignore(); getline (cin,s2);
   }
   else if (op == '^') cin >> y;


   for (int f = 0; f < s2.size(); f++)
  {

  if (s2[f] == ';') o++;

  }
  for (int q = 0; q < s2.size(); q++)
  {
      if (s2[q] == ' ') p++;
  }
 o = o+1;
 p = (p/o)+1;

  s2.erase(0, 1); //to remove  first bracket

  for (int e = 0; e < s2.size(); e++) //to replace characters with a space
  {
       if (s2[e] == ';' || s2[e] == ']') s2[e] = ' ';
  }
    string token2;
    float matrix2 [o*p];
    float h;
    for (int c = 0; c <o*p; c++)
   {
    token2 = s2.substr(0, s2.find(" "));
    h = atof(token2.c_str());
    matrix2 [c] = h;
    s2.erase(0, s2.find(" ")+1);
   }
 if ( n == o && m == p && op == '+')
 {
     ADD(matrix1,matrix2,m*n) //Where I got the error Cannot convert 'float*' to 'float' for argument '1'

 }
return 0;
}
 string ADD (float matrix1[],float matrix2[],int arraySize)
{
     string str;
     for (int u = 0; u < arraySize; u++)
     {
     float matrix3[arraySize];
     matrix3[u] = matrix1[u] + matrix2[u];

     ostringstream ss;
     ss << matrix3;
     str = ss.str();
     return str;
     }
    cout <<str;
}

Answer 1

您的前向声明与您的函数定义不符：

string ADD (float matrix1,float matrix2,int arraySize);

和

string ADD (float matrix1[],float matrix2[],int arraySize)
{
...
}

只需更改您的前向声明以匹配该定义。

错误：无法将参数“ 1”的“ float *”转换为“ float”

1 个答案: