Question

我有一个JSON文件A.json，其中包含多个字典。我想从键“模型” grouped by brand中删除常见的键值对。

例如，考虑以下品牌：“福特”：

{"Number": '123', "brand": "Ford", "model":{"Mustang1":"2.64", "Mustang2":"3.00", "Mustang3":"1.00", "Mustang4":"1.64"}}

{"Number": '891', "brand": "Ford", "model":{"Mustang1":"2.64", "Mustang8":"3.00", "Mustang3":"1.00", "Mustang6":"1.64"}}

两个字典中共有的键model中的键是Mustang1和Mustang3。因此，我从模型中删除了两个键值对。最终字典为：

 {"Number": '123', "brand": "Ford", "model":{"Mustang2":"3.00", "Mustang4":"1.64"}}
{"Number": '891', "brand": "Ford", "model":{"Mustang8":"3.00", "Mustang6":"1.64"}}

A.json

{"Number": '123', "brand": "Ford", "model":{"Mustang1":"2.64", "Mustang2":"3.00", "Mustang3":"1.00", "Mustang4":"1.64"}}
{"Number": '321', "brand": "Toyota", "model":{"Camry":"2.64", "Prius":"3.00", "Corolla":"1.00", "Tundra":"1.64"}}
{"Number": '111', "brand": "Honda", "model":{"Accord":"2.64", "Civic":"3.00", "Insight":"1.00", "Pilot":"1.64"}}
{"Number": '891', "brand": "Ford", "model":{"Mustang1":"2.64", "Mustang8":"3.00", "Mustang3":"1.00", "Mustang6":"1.64"}}
{"Number": '745', "brand": "Toyota", "model":{"Camry":"2.64", "Sienna":"3.00", "4Runner":"1.00", "Prius":"1.64"}}
{"Number": '325', "brand": "Honda", "model":{"Accord":"2.64", "Passport":"3.00", "HR-V":"1.00", "Pilot":"1.64"}}
{"Number": '745', "brand": "Accura", "model":{"TLX":"2.64", "MDX":"3.00"}}
{"Number": '325', "brand": "Accura", "model":{"TLX":"2.64", "MDX":"3.00"}}

预期结果： Result.json

{"Number": '123', "brand": "Ford", "model":{"Mustang2":"3.00", "Mustang4":"1.64"}}
{"Number": '321', "brand": "Toyota", "model":{"Corolla":"1.00", "Tundra":"1.64"}}
{"Number": '111', "brand": "Honda", "model":{"Civic":"3.00", "Insight":"1.00", "Pilot":"1.64"}}
{"Number": '891', "brand": "Ford", "model":{"Mustang8":"3.00", "Mustang6":"1.64"}}
{"Number": '745', "brand": "Toyota", "model":{"Sienna":"3.00", "4Runner":"1.00"}}
{"Number": '325', "brand": "Honda", "model":{"Passport":"3.00", "HR-V":"1.00", "Civic Type R":"1.64"}}
{"Number": '745', "brand": "Accura", "model":{}}
{"Number": '325', "brand": "Accura", "model":{}}

Answer 1

首先，您的A.json不是常规的json文件。这是更正的版本：

[{"Number": "123", "brand": "Ford", "model":{"Mustang1":"2.64", "Mustang2":"3.00", "Mustang3":"1.00", "Mustang4":"1.64"}},
{"Number": "321", "brand": "Toyota", "model":{"Camry":"2.64", "Prius":"3.00", "Corolla":"1.00", "Tundra":"1.64"}},
{"Number": "111", "brand": "Honda", "model":{"Accord":"2.64", "Civic":"3.00", "Insight":"1.00", "Pilot":"1.64"}},
{"Number": "891", "brand": "Ford", "model":{"Mustang1":"2.64", "Mustang8":"3.00", "Mustang3":"1.00", "Mustang6":"1.64"}},
{"Number": "745", "brand": "Toyota", "model":{"Camry":"2.64", "Sienna":"3.00", "4Runner":"1.00", "Prius":"1.64"}},
{"Number": "325", "brand": "Honda", "model":{"Accord":"2.64", "Passport":"3.00", "HR-V":"1.00", "Pilot":"1.64"}},
{"Number": "745", "brand": "Accura", "model":{"TLX":"2.64", "MDX":"3.00"}},
{"Number": "325", "brand": "Accura", "model":{"TLX":"2.64", "MDX":"3.00"}}]

文件内容应使用json模块进行解析：

import io # to test without a file
f = io.StringIO(json_text) # json_text is a string containing the text above

import json
ds = json.load(f)

第二，您必须按品牌建立set通用模型：

common_by_brand = {}
for d in ds:
    if d["brand"] in common_by_brand:
        common_by_brand[d["brand"]] &= set(d["model"])
    else:
        common_by_brand[d["brand"]] = set(d["model"])
    # {'Ford': {'Mustang1', 'Mustang3'}, 'Toyota': {'Camry', 'Prius'}, 'Honda': {'Accord', 'Pilot'}, 'Accura': {'TLX', 'MDX'}}

第三，只需遍历列表并删除那些常见模型：

for d in ds:
    common = common_by_brand[d["brand"]]
    d["model"] = {k: v for k, v in d["model"].items() if k not in common}
# [{'Number': '123', 'brand': 'Ford', 'model': {'Mustang2': '3.00', 'Mustang4': '1.64'}}, {'Number': '321', 'brand': 'Toyota', 'model': {'Corolla': '1.00', 'Tundra': '1.64'}}, {'Number': '111', 'brand': 'Honda', 'model': {'Civic': '3.00', 'Insight': '1.00'}}, {'Number': '891', 'brand': 'Ford', 'model': {'Mustang8': '3.00', 'Mustang6': '1.64'}}, {'Number': '745', 'brand': 'Toyota', 'model': {'Sienna': '3.00', '4Runner': '1.00'}}, {'Number': '325', 'brand': 'Honda', 'model': {'Passport': '3.00', 'HR-V': '1.00'}}, {'Number': '745', 'brand': 'Accura', 'model': {}}, {'Number': '325', 'brand': 'Accura', 'model': {}}]

第四，将结果以json格式写入文件：

g = io.StringIO()
json.dump(ds, g)
print (g.getvalue())

格式化输出：

[{"Number": "123", "brand": "Ford", "model": {"Mustang2": "3.00", "Mustang4": "1.64"}},
{"Number": "321", "brand": "Toyota", "model": {"Corolla": "1.00", "Tundra": "1.64"}},
{"Number": "111", "brand": "Honda", "model": {"Civic": "3.00", "Insight": "1.00"}},
{"Number": "891", "brand": "Ford", "model": {"Mustang8": "3.00", "Mustang6": "1.64"}},
{"Number": "745", "brand": "Toyota", "model": {"Sienna": "3.00", "4Runner": "1.00"}},
{"Number": "325", "brand": "Honda", "model": {"Passport": "3.00", "HR-V": "1.00"}},
{"Number": "745", "brand": "Accura", "model": {}},
{"Number": "325", "brand": "Accura", "model": {}}]

Answer 2

首先，您需要使用json builtin library在python中加载json。

然后，有几种方法可以实现此目的。例如，您可以遍历每个字典并在每次迭代时更新Counter。然后，您删除已被多次计数的每个键。

最后，您再次使用json lib将结果字典转储到新文件中。

Answer 3

我假设您将使用标准JSON格式。您需要检查字典中type中value的{{1}}的类型为key。 dict方法可用于此目的。您可以使用以下代码段：

isinstance()

我希望这可能有用。干杯:)

根据python中字典的分组删除键/值对

3 个答案: