我需要以一种可读的方式总结多年来所有月份中每个月的采访次数。
SELECT month(i.Date) AS Month, Year(i.Date) AS Year, Count(i.Id) AS' Number of Interviews'
FROM Interviews i
GROUP BY month(i.Date), year(i.Date)
ORDER BY year(i.Date) DESC, month(Date) ASC
我希望查询以类似于“ January”的VARCHAR形式返回Month,而不是“ month”函数的默认INT。
答案 0 :(得分:1)
对于 MySql ,它是:
SELECT
monthname(i.Date) AS Month,
Year(i.Date) AS Year,
Count(i.Id) AS `Number of Interviews`
FROM Interviews i
GROUP BY month(i.Date), monthname(i.Date), year(i.Date)
ORDER BY year(i.Date) DESC, month(i.Date) ASC
对于 SQL Server :
SELECT
datename(month, i.date) AS Month,
Year(i.Date) AS Year,
Count(i.Id) AS [Number of Interviews]
FROM Interviews i
GROUP BY month(i.Date), datename(month, i.date), year(i.Date)
ORDER BY year(i.Date) DESC, month(i.Date) ASC
答案 1 :(得分:0)
适用于大多数DBMS的解决方案是CASE
表达式。
SELECT CASE month(i.date)
WHEN 1 THEN
'January'
...
WHEN 12 THEN
'December'
END month,
year(i.date) year,
count(i.id) number_of_interviews
FROM interviews i
GROUP BY month(i.date),
year(i.date)
ORDER BY year(i.date) DESC,
month(i.date) ASC;
答案 2 :(得分:0)
SELECT count(1),格式(dateColumn,“ yyyy-MM”) FROM tableName GROUP BY格式(dateColumn,“ yyyy-MM”) 按2排序