Question

我想检索单引号内的字符串，例如在句子中：

Play 'My lady's on fire' by Ty Segall

我要检索：

My lady's on fire

我想忽略带有's和't的单词，例如“不要”和“女士的”：

我尝试过：

re.findall(r"\s\'.*?\'", user_input)

但是，我得到：

[ 'My lady']

我想得到：

[My lady's on fire]

Answer 1

https://github.com/endeneer1/google-form-autofilling-spam-bot-using-Python-multiple-choice-questions/blob/master/google-form-spambot.py

\B assert position where \b does not match
' matches the character ' literally (case sensitive)
Non-capturing group (?:[^']*(?:'\b)?)+
+ Quantifier — Matches between one and unlimited times, as many times as possible, giving back as needed (greedy)
Match a single character not present in the list below [^']*
* Quantifier — Matches between zero and unlimited times, as many times as possible, giving back as needed (greedy)
' matches the character ' literally (case sensitive)
Non-capturing group (?:'\b)?
? Quantifier — Matches between zero and one times, as many times as possible, giving back as needed (greedy)
' matches the character ' literally (case sensitive)
\b assert position at a word boundary: (^\w|\w$|\W\w|\w\W)
' matches the character ' literally (case sensitive)

Answer 2

您可以使用此正则表达式---> \b\s'(.*?)(?=\'\s|\'$) 您可以在https://pythex.org/

上对其进行测试

Python代码：

import re user_input = "Play 'My lady's on fire' by Nipsey Hussle Play 'My lady's on fire'" print(re.findall(r"\b\s'(.*?)(?=\'\s|\'$)",user_input))

Answer 3

根据您的要求，这是一种替代方法（可能不是性能最高的一种）：

\'(?:(?!\'[^st]).)*\'

从本质上讲，您一直在使用字符，直到找到一个以'开头且后面没有 s 或 t 的序列。

如果您需要考虑词边界的更一般的情况，请查看其他答案。

如何获取单引号内的字符串但忽略“”和“'t”？

3 个答案: