任务是将学生的家庭作业SQL文件与导师SQL文件进行比较。
我写了两个函数，它们返回一个二维数组（第一个元素是绝对路径，第二个是相对路径）。然后，如果这些值相等，我将比较学生和导师的相对路径，并执行SQL文件（使用绝对路径查找）
还有更优雅的实现吗？
指导者目录的文件夹结构：
Homework (folder)
├ 1 (folder)
| ├ 1.sql
| ├ 2.sql
| └ n.sql
├ 2 (folder)
| ├ 1.sql
| ├ 2.sql
| └ n.sql
├ n (folder)
| ├ 1.sql
| ├ 2.sql
| └ n.sql
学生目录的文件夹结构：
├Students Homework (folder)
├Student1(folder)
├ 1 (folder)
| ├ 1.sql
| ├ 2.sql
| └ n.sql
├ 2 (folder)
| ├ 1.sql
| ├ 2.sql
| └ n.sql
├ n (folder)
| ├ 1.sql
| ├ 2.sql
| └ n.sql
├Student2(folder)
├ 1 (folder)
| ├ 1.sql
| ├ 2.sql
| └ n.sql
├ 2 (folder)
| ├ 1.sql
| ├ 2.sql
| └ n.sql
├ n (folder)
| ├ 1.sql
| ├ 2.sql
| └ n.sql
“导师”功能：
def find_mentors_sql(config):
mentors_sql_abs = []
mentors_sql_rel = []
for dirpath, subdirs, files in walk(config["MAIN_DIR"] + '\\Homework'):
mentors_sql_abs.extend(path.join(dirpath, x) for x in files if x.endswith(".sql"))
mentors_sql_rel.extend(path.join(path.basename(dirpath), x) for x in files if x.endswith(".sql"))
mentors_sql = [[0] * 2 for i in range(len(mentors_sql_abs))]
iter = 0
for _ in mentors_sql_abs:
mentors_sql[iter][0] = mentors_sql_abs[iter]
iter += 1
iter1 = 0
for _ in mentors_sql_rel:
mentors_sql[iter1][1] = mentors_sql_rel[iter1]
iter1 += 1
return mentors_sql
“学生”功能（逻辑与上一个相似：
def find_students_sql(config):
students_sql_abs = []
students_sql_rel = []
for dirpath, subdirs, files in walk(config["MAIN_DIR"] + '\\Students Homework'):
students_sql_abs.extend(path.join(dirpath, x) for x in files if x.endswith(".sql"))
students_sql_rel.extend(path.join(path.basename(dirpath), x) for x in files if x.endswith(".sql"))
students_sql = [[0] * 2 for i in range(len(students_sql_abs))]
iter = 0
for _ in students_sql:
students_sql[iter][0] = students_sql_abs[iter]
iter += 1
iter1 = 0
for _ in students_sql:
students_sql[iter1][1] = students_sql_rel[iter1]
iter1 += 1
return students_sql