Question

我有onclick事件的警报。但是我希望警报持续两秒钟，并在2秒后自动关闭。如何在reactJS中设置警报超时时间？


const handleHide1 = () => this.setState({ show1: false });
const handleShow1 = () => this.setState({ show1: true });

return(
<div>
<Alert show={this.state.show1} variant="success" style={{marginTop:'2%'}} onHide={this.handleHide1} >
<Alert.Heading closeButton>Order Accepted
<button type="button" class="close" onClick={handleHide1} aria-label="Close">
<span aria-hidden="true">&times;</span></button>
</Alert.Heading>                  
<p>Thank you for Accepting Order. We will inform the customer</p>
</Alert>

<Button variant="outline-success" onClick={()=>{handleShow1}>Accept</Button>

Answer 1

像这样？：

const handleShow1 = () => {
  this.setState({
     show1: true
  })

  setTimeout(() => {
     this.setState({
         show1: false
     })
  }, 2000)

}

这也是我为您准备的一个沙盒，让您对它有所了解： https://codesandbox.io/s/2w03nvvjnp

如何在reactJS中设置timeInterval / timeOut来发出警报？

1 个答案: