我想计算总行数,样本:
row1 = 1
row2 = 1
row3 = -1
row4 = 1
row5 = -1
总计= 1,因为1 + 1 +( - 1)+1 +( - 1)= 1
我想从数据库中计算
我的代码是:
<? $result_count_like = mysql_query("SELECT * FROM like_mood WHERE img_id='$imageid'");
while($row_like_co = mysql_fetch_array($result_count_like))
{
$total_num=$row_like_co['mood_num']; // THIS IS ROWS NAME
}
?>
谢谢:)
答案 0 :(得分:2)
...试
SELECT SUM(mood_num) FROM like_mood WHERE img_id= '$imageid'
例如..
$sql = mysql_query("SELECT SUM(mood_num) FROM like_mood WHERE img_id= '$imageid'");
$sql = mysql_fetch_array($sql);
$total = $sql[0];
答案 1 :(得分:0)
<?
$toCount = array();
$result_count_like = mysql_query("SELECT * FROM like_mood WHERE img_id='$imageid'");
while($row_like_co = mysql_fetch_array($result_count_like))
{
$toCount[]=$row_like_co['mood_num']; // THIS IS ROWS NAME
}
echo array_sum($toCount);
?>