Question


def mult(numbers):
        return [10] * len(numbers)

number = [1,2,5,6,7,8,10]
mult(number)

我希望输出[10,20,50.......] 但这是我得到的[10, 10, 10, 10, 10, 10, 10]

的输出

Answer 1

这里是您正在做的事情，带有注释：

def mult(numbers):
    return [10] * len(numbers)
    # [10]                -->  Take the list [10]
    # len(numbers)        -->  Take the length of the list `numbers`, which has 7 elements
    # [10] * len(numbers) -->  repeat [10] seven times, to get [10, 10, 10, 10, 10, 10, 10]

我认为问题是您误解了len()函数的功能以及*（乘法）运算符如何与列表一起使用。如果要将每个数字乘以10，则应执行以下操作：

def mult(numbers):
    multed = []                 # create an empty list to store the result
    for num in numbers:         # iterate through the elements in `numbers` one by one
        multed.append(10 * num) # add (10 * element) to our new list
    return multed               # return the list we've created

Python还具有 list comprehensions ，可以使这段代码更加简洁：

def mult(numbers):
    return [10*num for num in numbers]
    # this does the same thing as above

Answer 2

这就是我要做的

def mult(numbers):
    return [10*i for i in numbers]
number = [1,2,5,6,7,8,10]
mult(number)

您的方法只是获取值10并复制等于输入数组len的次数。

Answer 3

我认为您应该尝试这种方式。

def mult(number):
     return 10 * number

number = [1,2,5,6,7,8,10]
answer = []

for i in number:
    answer.append(mult(i))

print(answer)

我该如何解决此问题。我正在尝试使用len函数，但无法正常运行

3 个答案: