为什么我不能实现Google Places API?

时间:2019-04-28 02:38:34

标签: java android google-places-api

我正在尝试通过Google实现Place Picker API。但是每次我开始活动时,活动都会立即关闭。

用于实现位置选择器的代码:

int PLACE_PICKER_REQUEST = 1;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_pop_up_2);

    btn3 = (Button) findViewById(R.id.button2);
     btn3.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            PlacePicker.IntentBuilder builder = new PlacePicker.IntentBuilder();
            Context context = getApplicationContext();
            try {
                startActivityForResult(builder.build(context), PLACE_PICKER_REQUEST);
            } catch (GooglePlayServicesRepairableException e) {
                e.printStackTrace();
            } catch (GooglePlayServicesNotAvailableException e) {
                e.printStackTrace();
            }
        }
    });
    }
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {

        if (requestCode == PLACE_PICKER_REQUEST) {
        if (resultCode == RESULT_OK) {
            Place place = PlacePicker.getPlace(data, this);
            String toastMsg = String.format("Place: %s", place.getName());
            Toast.makeText(this, toastMsg, Toast.LENGTH_LONG).show();
        }
    }

}

API密钥已在清单文件中声明:

<manifest>

<application

        <meta-data
        android:name="com.google.android.geo.API_KEY"
        android:value="@string/google_place_api" />
</application>
</manifest>

Logcat错误:

    BasicNetwork.performRequest: Unexpected response code 403 for https://www.googleapis.com/placesandroid/v1/search?key=AIzaSyCHWpRWCGo_YUKwzHn4Qv6yP5q9E5TNRJA
2019-04-28 07:49:21.729 2875-5225/? E/Places: Places API for Android does not seem to be enabled for your app. See https://developers.google.com/places/android/signup for more details.

即使在我的帐户上启用了Google地方信息,为什么也会出现此错误?

注意:我还设置了我的结算帐户。

1 个答案:

答案 0 :(得分:0)

您的应用似乎未启用Android的Places API:请仔细检查

class(x)