嵌套函数-参数缺少参数

Question

我一直在尝试在另一个函数中创建一个函数，其中getPoolInfo的输出将为（Func1：Double，Func2：Double）。

我真的需要你的帮助。

func getPoolInfo(PoolLength:Double, PoolWidth:Double, ShallowDepth:Double,DeepDepth:Double)->(Double,Double)
{

//To calculate the Area of the Pool
func Area(PoolLength:Double,PoolWidth:Double)-> Double
{
    let area = PoolLength * PoolWidth
    return area
}

//To calculate the Volume of the Pool
func poolVolume(PoolLength:Double, PoolWidth:Double, ShallowDepth:Double,DeepDepth:Double)->Double{

    let area = PoolLength * PoolWidth
    let avgDepth = ((ShallowDepth + DeepDepth) / 2)
    let volume = area * avgDepth


    return volume
}

return (Area(),poolVolume())

}

getPoolInfo（PoolLength：12，PoolWidth：6，ShallowDepth：1，DeepDepth：3）

  

缺少参数的参数

Answer 1

更改

return (Area(),poolVolume())

到

return (Area(PoolLength:PoolLength,PoolWidth:PoolWidth),poolVolume(PoolLength:PoolLength, PoolWidth:PoolWidth, ShallowDepth:ShallowDepth,DeepDepth:DeepDepth))