Spring boot(2.2 MI)安全性:为HttpBasic

时间:2019-04-27 15:47:55

标签: spring-boot spring-security http-basic-authentication

我的Spring Boot(2.2 MI版)应用程序仅具有使用Spring Security通过httpBasic进行身份验证的REST端点。但是,当由于未启用用户等原因导致用户身份验证失败时,我想使用自定义Json进行响应,以便我的React Native应用程序适当地指导用户。但是,自定义AuthenticationFailureHandler似乎只能针对formLogin进行配置。

我只看到类似的例子

http.
   formLogin().
       failureHandler(customAuthenticationFailureHandler());

public class CustomAuthenticationFailureHandler
   implements AuthenticationFailureHandler {
       @Override
       public void onAuthenticationFailure(
           HttpServletRequest request,
           HttpServletResponse response,
           AuthenticationException exception)
           throws IOException, ServletException {
       }
}
@Bean
public AuthenticationFailureHandler customAuthenticationFailureHandler() {
    return new CustomAuthenticationFailureHandler();
}

但是,我需要下面类似的东西(似乎没有东西)

http.
   httpBasic().
       failureHandler(customAuthenticationFailureHandler());

请让我知道,前进的最佳方法是什么?

更新:- 按照下面接受的答案,以下是自定义实现CustomBasicAuthenticationEntryPoint

import javax.servlet.ServletException;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;

public class CustomBasicAuthenticationEntryPoint extends BasicAuthenticationEntryPoint {
    @Override
    public void commence(HttpServletRequest request, HttpServletResponse response,
                         AuthenticationException authException) throws IOException, ServletException {
        response.addHeader("WWW-Authenticate", "Basic realm=\"" + this.getRealmName() + "\"");
        //response.sendError( HttpStatus.UNAUTHORIZED.value(), "Test msg response");
        response.setStatus(HttpServletResponse.SC_UNAUTHORIZED);
        response.setContentType("application/json");
        response.setCharacterEncoding("UTF-8");
        response.getWriter().write("{ \"val\":\"Venkatesh\"}");
    }
}

@Bean
    public AuthenticationEntryPoint customBasicAuthenticationEntryPoint() {
        CustomBasicAuthenticationEntryPoint obj = new CustomBasicAuthenticationEntryPoint();
        obj.setRealmName("YourAppName");
        return obj;
    }

protected void configure(HttpSecurity http) throws Exception{
        http.httpBasic().
                authenticationEntryPoint(customBasicAuthenticationEntryPoint());
}

1 个答案:

答案 0 :(得分:1)

BasicAuthenticationFilter认证失败时,它将调用AuthenticationEntryPoint。默认值是BasicAuthenticationEntryPoint,您可以考虑编写自定义值或扩展自定义值:

@Bean
public AuthenticationEntryPoint customBasicAuthenticationEntryPoint() {
    return new CustomBasicAuthenticationEntryPoint();
}

并通过以下方式进行配置:

   http.httpBasic().authenticationEntryPoint(customBasicAuthenticationEntryPoint())