Question

我有一个文本文件，需要用空格替换数字。

我尝试先将文本文件拆分为单个单词，然后检查该单词是否为数字

   def replace_digits_symbols():
    text_file = open_file()
    for word in text_file:
       for char in word:
         if char.isdigit():
             word.replace(char, " ")
      print(text_file)

应该用空格代替它们，但什么也没发生

Answer 1

str.replace方法仅返回替换的字符串，而无需就地更改原始字符串，这就是为什么调用word.replace(char, " ")不会执行任何操作的原因。相反，您可以将str.join与生成器表达式一起使用，该表达式迭代一行中的每个字符并输出空格而不是原始字符（如果它是数字）：

with open('file') as file:
    for line in file:
        print(''.join(' ' if char.isdigit() else char for char in line))

Answer 2

这是此过程的完整代码，

def helper(text):
    import string
    for digit in string.digits:
        text = text.replace(digit, ' ')
    return text

def ReplaceDigits(fileName):
    output_file = open("processed.txt",'w')
    lineNo = 1
    with open(fileName) as file_ptr:
        for lines in file_ptr:
            print("Processing Line No : {}".format(lineNo))
            lines = helper(lines)
            output_file.write(lines)
            lineNo +=1
ReplaceDigits("test.txt")

test.txt包含

this1is5sample0text
this10is552sample0text
this10is5sample0text
this10is52sample0text
this0is52sample0text

结果是

this is sample text
this  is   sample text
this  is sample text
this  is  sample text
this is  sample text

替换文字中的数字

2 个答案: