Question

我有一个网站，在该网站中，根据解析到URL的查询字符串创建了会话。我正在读取会话值，因此想要更改网站的标题。事情可以在下面的代码下正常运行，但不会进入elseif条件。如果我尝试打印会话值，它会给我正确的回显，但条件不能正常工作。它可以与If和else一起使用，但不能进入ElseIf

override func viewDidLoad() {
  super.viewDidLoad()
  refRepairs = Database.database().reference().child("repairs");

  //observing the data changes
  refRepairs!.observe(DataEventType.value, with: { (snapshot) in

    ...

Answer 1

您的条件不正确，请结合使用：

if(isset($_SESSION["mycid"]) && $_SESSION["mycid"] == "14")
...
elseif(isset($_SESSION["mycid"]) && $_SESSION["mycid"] == "8")

更有效的方法是只检查外部if中的isset一次，然后检查值：

if(isset($_SESSION["mycid"]))
{
        if($_SESSION["mycid"] == "14")
        {
             ...    
        }
        elseif($_SESSION["mycid"] == "8")
        {
             ...
        }
        else
        {
             ...
        }
}
else
{
       //action for $_SESSION["mycid"] not set
}

Answer 2

尝试一下

if (isset($_SESSION["mycid"])) {
    switch ($_SESSION["mycid"]) {
        case 7:
            $storeTitle = "Jet Airways BrandSTORE";
            $storeDLogo = "/images/jetAirwaysLogo.jpg";
            $storecolor1 = "#000"; //applied in header background
            $storecolor2 = "#FF9304"; //applied in mini header background 
            $storeGDlogo = "/images/globaJLinkerLogo.jpg";
            $storeGMlogo = "/images/globaJLinkerLogo.jpg";
            break;
        case 8:
            $storeTitle = "Jet Airways BrandSTORE";
            $storeDLogo = "/images/jetAirwaysLogo.jpg";
            $storeGDlogo = "/images/globaJLinkerLogo.jpg";
            $storeGMlogo = "/images/globaJLinkerLogo.jpg";
            break;
        case 9:
            $storeTitle = "Jet Airways BrandSTORE";
            $storeDLogo = "/images/jetAirwaysLogo.jpg";
            $storeGDlogo = "/images/globaJLinkerLogo.jpg";
            $storeGMlogo = "/images/globaJLinkerLogo.jpg";
            break;
        case 10:
            $storeTitle = "Jet Airways BrandSTORE";
            $storeDLogo = "/images/jetAirwaysLogo.jpg";
            $storeGDlogo = "/images/globaJLinkerLogo.jpg";
            $storeGMlogo = "/images/globaJLinkerLogo.jpg";
            break;
        case 14:
            $storeTitle = "Federation of Indian Exports Organization BrandSTORE";
            $storeDLogo = "/images/hid/figo-14.jpg";
            $storecolor1 = "#02ADF2"; //applied in header background
            $storecolor2 = "#FF9304"; //applied in mini header background 
            $storeGDlogo = "/images/hid/gl-14.jpg";
            $storeGMlogo = "/images/hid/gl-m-14.jpg";
            break;
    }
} else {
    $storeDLogo = "/images/jetAirwaysLogo.jpg";
    $storeGDlogo = "/images/globaJLinkerLogo.jpg";
    $storeGMlogo = "/images/globaJLinkerLogo.jpg";
}

在这里，请不要忘记传递default values，由于variables未能设置condition

PHP管理IF Else条件

2 个答案: