Question

我要在我的sdl应用程序中放置一个图像，为此，我需要知道它的路径。当我将完整路径放入IMG_Load()函数中时，它将起作用。当我尝试使用windows.h函数GetModuleFileName()并将其与另一个字符数组结合在一起时，我得到：

C：\ Users \ micro 电容器\源\存储库\ FlatApoc \ x64 \ Debug \ FlatApoc.exe / Images / Play1.png

我要解决的问题是摆脱

FlatApoc.exe

从char数组。我已经知道

FlatApoc.exe

来自GetModuleFileName()。解决此问题的方法只是从char数组中删除FlatApoc.exe，但是我对C ++还是很陌生，我不知道该怎么做。

我的代码是：

char path[MAX_PATH]; // The path of the executable
GetModuleFileName(NULL, path, sizeof(path)); // Get the path
char pathbuff[256]; // Buffer for the png file
strncpy_s(pathbuff, path, sizeof(pathbuff));
strncat_s(pathbuff, "/Images/Play1.png", sizeof(pathbuff));
Button_Play1 = IMG_Load(pathbuff);

Answer 1

C ++方式。注意它看起来更自然：

#include <windows.h>
#include <iostream>
#include <string>
#include <algorithm>

int main()
{
    char path [MAX_PATH];
    GetModuleFileName (NULL, path, sizeof (path));
    std::string s = path;
    auto n = s.rfind ('\\');
    s.erase (n);
    s += "/Images/Play1.png";
    std::cout << s;
}

Live demo

Answer 2

Nvm。我现在修复了它，但是我将代码留在这里：

char path[MAX_PATH]; // The path of the executable
GetModuleFileName(NULL, path, sizeof(path)); // Get the path
char search[] = "\\FlatApoc.exe"; // The programs name
char *ptr = strstr(path, search);
*ptr = NULL;

char pathbuff[256]; // Buffer for the png file
strncpy_s(pathbuff, path, sizeof(pathbuff));
strncat_s(pathbuff, "/Images/Play1.png", sizeof(pathbuff)); // "/Images/Play1.png" was the link from the executables folder
Button_Play1 = IMG_Load(pathbuff); // Load image

从char数组中删除单词

2 个答案: