Question

有人可以帮助我在这里找到我做错了什么。我必须解析以下XML字符串

<?xml version="1.0" encoding="UTF-8"?>
<Person>
   <isActive>true</isActive>
   <id>A01222262</id>
   <name>Bob</name>
   <addresses>
      <address>
         <attributeName>NEWYORK_ADDRESS</attributeName>
         <attributeValue>NY 10003</attributeValue>
      </address>
      <address>
         <attributeName>CALIFORNIA_ADDRESS</attributeName>
         <attributeValue>CA 92336</attributeValue>
      </address>
   </addresses>
</Person>

为此，我要映射三个bean，如下所示

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(
        name = "",
        propOrder = {"isActive", "id", "name", "addresses"}
)
@XmlRootElement(
        name = "Person"
)
public class Person {
    protected boolean isActive;
    @XmlElement(
            name = "Id"
    )
    protected String id;
    protected String name;
    protected Addresses addresses;
// All Setter and Getter
}

地址类如下所示

    @XmlAccessorType(XmlAccessType.FIELD)
    @XmlType(
            name = "Addresses",
            propOrder = {"address"}
    )
    public class Addresses {
        @XmlElement(
                required = true
        )
        protected List<Address> address;
    //All Setter Getter 
}

地址类如下所示

    @XmlAccessorType(XmlAccessType.FIELD)
    @XmlType(
            name = "",
            propOrder = {"attributeName", "attributeValue"}
    )
    public class Address {
        @XmlElement(
                required = true
        )
        protected String attributeName;
        @XmlElement(
                required = true
        )
        protected String attributeValue;
    //All Setter Getter 
}

这是我在解析时遇到的异常

com.fasterxml.jackson.databind.exc.MismatchedInputException：无法构造console.interceptor.Address的实例（尽管至少存在一个创建者）：不存在用于以下操作的字符串参数构造函数/工厂方法从[来源：]的字符串值（'NEWYORK_ADDRESS'）反序列化（StringReader）;行：1，列：173]（通过参考链： console.interceptor.Person [“ addresses”]-> console.interceptor.Addresses [“ address”]-> java.util.ArrayList [0]）

我正尝试解析如下

XmlMapper xmlMapper=new XmlMapper();
xmlMapper.enable(DeserializationFeature.ACCEPT_EMPTY_STRING_AS_NULL_OBJECT);
Person p=xmlMapper.readValue(xmlString,Person.class);  // xmlSting

我正在使用2.9.8版的jackson-dataformat-xml。

Answer 1

我尝试了您的课程并且能够像下面一样解析它。我再次检查了版本2.9.8并进行了确认。干杯！

public class StackOverFlowTest {
    public static void main(String[] args){
    JacksonXmlModule module = new JacksonXmlModule();
    module.setDefaultUseWrapper(false);
    XmlMapper xmlMapper = new XmlMapper(module);
    String xmlString="<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\"?><Person><isActive>true</isActive><id>A01222262</id><name>Bob</name><addresses><address><attributeName>NEWYORK_ADDRESS</attributeName><attributeValue>NY 10003</attributeValue></address><address><attributeName>CALIFORNIA_ADDRESS</attributeName><attributeValue>CA 92336</attributeValue></address></addresses></Person>";
        try {
        Person p=xmlMapper.readValue(xmlString,Person.class);
        System.out.println(p.toString());
    } catch (IOException e) {
        e.printStackTrace();
    }
}
}

使用Jackson解析XML时出现MismatchedInputException

1 个答案: