我需要传递几个参数作为WorkManager的输入,但是不知道如何。另外,我想通过存储库。
val data = workDataOf("cabinId" to task.cabinId)
val data2 = workDataOf("repository" to repository)
val uploadWorkRequest = OneTimeWorkRequestBuilder<WManager>()
.setInputData(data)
.setInputData(data2)
.build()
class WManager(appContext: Context, workerParams: WorkerParameters) : Worker(appContext, workerParams) {
override fun doWork(): Result {
val input = inputData.getInt("cabinId", 99)
val input2 = inputData("repository")
return Result.success(outputData)
}}
我试图为存储库实现可序列化的接口,但是它不起作用
答案 0 :(得分:1)
您在做正确的事。您可以将多个键值对传递给workDataOf
。
类似这样:
val data = workDataOf("cabinId" to task.cabinId, "repository" to repository)
val request = OneTimeWorkRequestBuilder<WManager>()
.setInputData(data)
.build()
WorkManager.getContext(context).enqueue(request)
这是假设repository
是可序列化的类型。如果没有,则需要进行依赖注入。