如何在正确处理NULL值的同时在LINQ中连接字符串

时间:2011-04-07 19:49:11

标签: linq null concatenation

我想要一种使用LINQ将多个列连接在一起的优雅方法,但是当任何列为NULL时使用+运算符或concat()会导致连接后的值为NULL。

有没有类似于concat()的方法,以不同的方式处理NULL,或者我是否以错误的方式考虑这个问题?

感谢任何帮助!

以下是我正在使用的代码:

List<CustomObject> objects = (
    from obj in ObjectTable
    where obj.Id == Id
    select new CustomObject()
    {
        EnteredBy = obj.EnteredBy, 
        EntryDate = obj.EntryDate, 
        WorknoteText = 
            obj.VchWorkNote1 +
            obj.VchWorkNote2 + 
            obj.VchWorkNote3 +
            obj.VchWorkNote4 +
            obj.VchWorkNote5 +
            obj.VchWorkNote6 +
            obj.VchWorkNote7 +
            obj.VchWorkNote8 +
            obj.VchWorkNote9 +
            obj.VchWorkNote10 +
            obj.VchWorkNote11 +
            obj.VchWorkNote12 +
            obj.VchWorkNote13 +
            obj.VchWorkNote14 +
            obj.VchWorkNote15 +
            obj.VchWorkNote16 +
            obj.VchWorkNote17 +
            obj.VchWorkNote18 +
            obj.VchWorkNote19 +
            obj.VchWorkNote20
    }).ToList();

5 个答案:

答案 0 :(得分:13)

一种选择是使用空合并运算符:

List<CustomObject> objects = (from o in ObjectTable
                              where o.Id == Id
                              select new CustomObject(){
                              EnteredBy = o.EnteredBy, 
                              EntryDate = o.EntryDate, 
                              WorknoteText = 
                              (o.VchWorkNote1 ?? "") +
                              (o.VchWorkNote2 ?? "") + 
                              (o.VchWorkNote3 ?? "") +
                              (o.VchWorkNote4 ?? "") +
                              ...
                              (o.VchWorkNote20 ?? "")
                              }).ToList();

希望生成的SQL将使用适当的翻译。

答案 1 :(得分:3)

您可以这样使用?? operator

...
(object.VchWorkNote5 ?? "") +
(object.VchWorkNote6 ?? "") +
(object.VchWorkNote7 ?? "") +
...

答案 2 :(得分:2)

您可以在数据库中添加新列吗?像“关键字”或“FullText”

之类的东西

定义它以进行计算,该计算基本上是"ISNULL(<Field1>, '') + ISNULL(<Field2>, '')"等。

确保将其标记为持久,因此不必每次都计算。

然后你只需要从你的桌子上拉下那一个字段。

答案 3 :(得分:2)

(object.VchWorkNote1 ?? "") + .....

怎么样?

答案 4 :(得分:0)

可能有一种更干净的方式,但首先想到的是快速零到零长度的字符串转换:

List<CustomObject> objects = (from object in ObjectTable
                         where object.Id == Id
                     select new CustomObject(){
                         EnteredBy = object.EnteredBy, 
                         EntryDate = object.EntryDate, 
                         WorknoteText = 
                         object.VchWorkNote1 ?? "" +
                         object.VchWorkNote2 ?? "" + 
                         object.VchWorkNote3 ?? "" +
                         object.VchWorkNote4 ?? "" +
                         object.VchWorkNote5 ?? "" +
                         object.VchWorkNote6 ?? "" +
                         object.VchWorkNote7 ?? "" +
                         object.VchWorkNote8 ?? "" +
                         object.VchWorkNote9 ?? "" +
                         object.VchWorkNote10 ?? "" +
                         object.VchWorkNote11 ?? "" +
                         object.VchWorkNote12 ?? "" +
                         object.VchWorkNote13 ?? "" +
                         object.VchWorkNote14 ?? "" +
                         object.VchWorkNote15 ?? "" +
                         object.VchWorkNote16 ?? "" +
                         object.VchWorkNote17 ?? "" +
                         object.VchWorkNote18 ?? "" +
                         object.VchWorkNote19 ?? "" +
                         object.VchWorkNote20 ?? ""
                     }).ToList();