Question

我想将总和结果转换为百分比。添加后，总计将达到100％。我已经按备注对它进行了分组，并且已经从查询中获得了总数。但是它仍然在数量上。

这是我的查询

SELECT
    CASE
        WHEN A.district = B.district THEN 'Delivered from store in same district'
        WHEN A.city = B.city THEN 'Delivered from store in same city'
        WHEN A.province = B.province THEN 'Delivered from store in same province'
        ELSE 'Not delivered from nearest store'
    END AS 'REMARK',
    SUM(CASE
        WHEN YEAR(T1.create_time) = '2019' AND MONTH(T1.create_time) = '01' THEN 1
        ELSE 0
    END) AS 'Jan-19',
    SUM(CASE
        WHEN YEAR(T1.create_time) = '2019' AND MONTH(T1.create_time) = '02' THEN 1
        ELSE 0
    END) AS 'Feb-19',
    SUM(CASE
        WHEN YEAR(T1.create_time) = '2019' AND MONTH(T1.create_time) = '03' THEN 1
        ELSE 0
    END) AS 'Mar-19', 
    SUM(CASE
        WHEN YEAR(T1.create_time) = '2019' AND MONTH(T1.create_time) = '04' THEN 1
        ELSE 0
    END) AS 'Apr-19'
FROM 
    au_store_add A
INNER JOIN
    (SELECT
        A.id,
        A.code,
        A.create_time,
        A.plat_create_time,
        A.appoint_stcode,
        A.status
        FROM deli_order A
        WHERE A.appoint_stcode IS NOT NULL
    UNION
        SELECT
        B.id,
        B.code,
        B.create_time,
        B.plat_create_time,
        B.destination_code,
        B.status
        FROM deli_order B
        WHERE B.destination_code IS NOT NULL) T1 ON T1.appoint_stcode = A.store_code
INNER JOIN
    deli_order_delivery B ON B.order_id = T1.id
WHERE 
    YEAR(T1.plat_create_time)='2019' and T1.status = 6 and (month(T1.plat_create_time) in (1,2,3,4))
GROUP BY
    CASE
        WHEN A.district = B.district THEN 'Delivered from store in same district'
        WHEN A.city = B.city THEN 'Delivered from store in same city'
        WHEN A.province = B.province THEN 'Delivered from store in same province'
        ELSE 'Not delivered from nearest store'
    END

结果是这样的

REMARK                                | Jan-19| Feb-19| Mar-19| Apr-19|
-----------------------------------------------------------------------
Delivered from store in same city        252      198    308      283
Delivered from store in same district    114      110    163      138 
Delivered from store in same province    1135     976    1387    1208
Not delivered from nearest store         3046     2518   3189    3123

我每个月都需要生成一个类似的东西（没有“总计”）

REMARK                                | Jan-19| 
-----------------------------------------------
Delivered from store in same city        5.5%     
Delivered from store in same district    2.5%     
Delivered from store in same province    25%     
Not delivered from nearest store         67%    
Grand Total                              4547  (100%)

我应该在查询中添加什么？

Answer 1

鉴于您正在使用MySQL 8+，则应该可以使用COUNT()作为分析功能。它在这里很方便：

SELECT
    CASE
        WHEN A.district = B.district THEN 'Delivered from store in same district'
        WHEN A.city = B.city THEN 'Delivered from store in same city'
        WHEN A.province = B.province THEN 'Delivered from store in same province'
        ELSE 'Not delivered from nearest store'
    END AS REMARK,
    100.0 * COUNT(CASE WHEN DATE_FORMAT(create_time, '%Y-%m') = '2019-01' THEN 1 END)
        / COUNT(CASE WHEN DATE_FORMAT(create_time, '%Y-%m') = '2019-01'
                     THEN 1 END) OVER () `Jan-19`,
    100.0 * COUNT(CASE WHEN DATE_FORMAT(create_time, '%Y-%m') = '2019-02' THEN 1 END)
        / COUNT(CASE WHEN DATE_FORMAT(create_time, '%Y-%m') = '2019-02'
                     THEN 1 END) OVER () `Feb-19`,
    100.0 * COUNT(CASE WHEN DATE_FORMAT(create_time, '%Y-%m') = '2019-03' THEN 1 END)
        / COUNT(CASE WHEN DATE_FORMAT(create_time, '%Y-%m') = '2019-03'
                     THEN 1 END) OVER () `Mar-19`,
    100.0 * COUNT(CASE WHEN DATE_FORMAT(create_time, '%Y-%m') = '2019-04' THEN 1 END)
        / COUNT(CASE WHEN DATE_FORMAT(create_time, '%Y-%m') = '2019-04'
                     THEN 1 END) OVER () `Apr-19`
FROM 
    au_store_add A
...

我使用上面的DATE_FORMAT来简化对年月的检查。我还用COUNT代替了SUM，这使我们可以使用略短的条件表达式。

将总和转换成百分比

1 个答案: