我只需要一次Ajax响应，当前再次执行相同的查询，我只希望在发送和geyying ajax响应后一次

Question

我正在发送ajax请求。到一个php页面，其中我使用while循环来获取所有数据，我想将数据减少1并更新exixing数据并插入到新表中，我只希望执行一次此操作，但是问题是更新和插入数据的次数更多。 / p>

    $("#create_button").click(function(){

             if (! confirm('Do You Want To Create Product?')) { return false;  preventDefault(); }else{
    $.ajax({
        type :'POST',
        url : 'response.php', //Here you will fetch records 
        //dataType:'json',
        data :{'select_id':select_id},
        success:function(response){
          //alert(response);





        }

    });
             }

 });
        }

in response.php

  <?php
include_once("../database/db.php");

if(isset($_POST["select_id"]))
 {
    $select_id=$_POST["select_id"];
 $get_product=$con1->query("SELECT * FROM `components` WHERE 
    FIND_IN_SET($select_id,product_id)");
    $i=1;
     while($row=$get_product->fetch(PDO::FETCH_ASSOC)){
      $component_id=$row['id'];
       $component_qty=$row['quantity_remain'];


     $sql = "UPDATE components SET quantity_remain=? WHERE id=?" ;
       $con1->prepare($sql)->execute([$component_qty - 1,$component_id]);


     $i++;
        }





            $sql = "INSERT INTO created_products (product_id) 
 VALUES (?)";
    $con1->prepare($sql)->execute([$select_id]);    
          unset($_POST["select_id"]);


}



    ?>