Question

我认为这个问题确实很简单，但是我不知道该怎么办。我有一个XPath元素，其编号序列为1到8。我需要一个一个地打开所有这些元素。

//*[@id="meio"]/div[2]/section/article[1]/h2/span/a[1]
//*[@id="meio"]/div[2]/section/article[2]/h2/span/a[1]
//*[@id="meio"]/div[2]/section/article[3]/h2/span/a[1]
//*[@id="meio"]/div[2]/section/article[4]/h2/span/a[1]
//*[@id="meio"]/div[2]/section/article[5]/h2/span/a[1]
//*[@id="meio"]/div[2]/section/article[6]/h2/span/a[1]
//*[@id="meio"]/div[2]/section/article[7]/h2/span/a[1]
//*[@id="meio"]/div[2]/section/article[8]/h2/span/a[1]

我正在尝试这样做：

while w > 0:
    i = 0
    a = str(i)
    while i < 8:
        i += 1
        driver.find_element_by_xpath('//*[@id="meio"]/div[2]/section/article[" + str(i) + "]/h2/span/a').click()
        driver.refresh()
        #there's more code after this, but I don't think it's necessary.

但是它执行了我在第一页上需要做的事情，然后返回并永远在第一页中循环播放。我无法单击XPath 2或除1之外的任何其他按钮。我在做什么错了？

每次循环开始时，我需要在XPath中增加一个数字，该怎么做？

Answer 1

这样的事情怎么办？

articles_with_links = driver.find_elements_by_xpath('//*[@id="meio"]/div[2]/section/article')

for article in articles_with_links:
    article.find_element_by_xpath('//h2/span/a').click()

如何在带有Python + Selenium的XPath中使用数字序列？

1 个答案: