Question

我在一个正在编程宾果游戏的项目（在C中）的中间，并且需要做的最后一个功能是检查是否有宾果游戏的功能。我有一个5 x 5生成的随机数数组，我通过用户输入生成一个随机数。如何使数组将该数字（如果实际上在数组中）更改为0，然后通过用户输入检查是否有宾果游戏？

这是生成数组的代码

for (int row = 0; row < 5; row++) {
        for(int column = 0; column < 5; column++) {
            if(row == 2 && column == 2) {
                board[row][column] = 0;
            } else {
                int num = rand() %15 + 1 +(column * 15);
                for(int i = 0; i < 75; i++) {
                    if(num == used[i]) {
                        num = rand() %15 + 1 +(column * 15);
                    }
                }
                board[row][column] = num;
                used[used_counter] = num;
                used_counter++;
            }
        }
    }

int generate_number(int boneyard[75], int *boneyard_counter) {
    int num = rand() %75 + 1;
    for (int i = 0; i <75; i++){
        if(num == boneyard[i]);
        num = rand() %75 + 1;
    }
    boneyard[*boneyard_counter] = num;
    boneyard_counter++;
    return num;
}

这是生成随机数的代码。

Answer 1

您将执行以下操作：

    int found_match = 0;
    for(int row = 0; row < 5; ++row){
        for(int column = 0; column < 5; ++column){
            if(board[row][column] == num){
                board[row][column] = 0;
                found_match = 1;
                goto loop_end;
            }
        }
    }
loop_end:
    if(found_match){
    /*
    Check all diagonals, rows, and columns to see if any one of them contains only zeroes,
    stopping if you find that a diagonal/row/column that does in fact contain only zeroes
    and informing the player that they've won.
    */
    }

如何检查阵列位置是否为特定数字

1 个答案: