我在使用Intent Action_Call时遇到麻烦。我将许可放到了清单中,但是没有用。我按按钮呼叫,但没有任何反应。我正在制作的应用程序是执行多个Intent的应用程序,因此代码不在MainActivity中。我不知道是否有帮助,但是我正在使用API 28。 感谢您的阅读。
清单:
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.example.intentsimplicitas">
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.CALL_PHONE"/>
<uses-permission android:name="android.permission.READ_SMS" />
<uses-permission android:name="android.permission.WRITE_SMS" />
<application
android:allowBackup="true"
android:icon="@mipmap/ic_launcher"
android:label="@string/app_name"
android:roundIcon="@mipmap/ic_launcher_round"
android:supportsRtl="true"
android:theme="@style/AppTheme">
<activity android:name=".SmsActivity"></activity>
<activity android:name=".DialActivity" />
<activity android:name=".WaysActivity" />
<activity android:name=".MapActivity" />
<activity android:name=".PageActivity" />
<activity android:name=".MainActivity">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>
JAVA(DialActivity.java)
public class DialActivity extends Activity {
Button btnDial;
EditText edtPhone;
String phone;
Intent it;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_dial);
btnDial = (Button)findViewById(R.id.btnDial);
edtPhone = (EditText)findViewById(R.id.edtPhone);
}
public void dialClick (View v) {
phone = edtPhone.getText().toString();
Uri uri = Uri.parse("tel: " + phone);
it = new Intent(Intent.ACTION_CALL);
it.setData(uri);
startActivity(it);
}
}
答案 0 :(得分:0)
来自https://developer.android.com/training/permissions/requesting:
请求权限:
// Here, thisActivity is the current activity
if (ContextCompat.checkSelfPermission(thisActivity,
Manifest.permission.CALL_PHONE)
!= PackageManager.PERMISSION_GRANTED) {
// Permission is not granted
// Should we show an explanation?
if (ActivityCompat.shouldShowRequestPermissionRationale(thisActivity,
Manifest.permission.CALL_PHONE)) {
// Show an explanation to the user *asynchronously* -- don't block
// this thread waiting for the user's response! After the user
// sees the explanation, try again to request the permission.
} else {
// No explanation needed; request the permission
ActivityCompat.requestPermissions(thisActivity,
new String[]{Manifest.permission.CALL_PHONE},
MY_PERMISSIONS_REQUEST_CALL_PHONE);
// MY_PERMISSIONS_REQUEST_CALL_PHONE is an
// app-defined int constant. The callback method gets the
// result of the request.
}
} else {
// Permission has already been granted
}
验证:
@Override
public void onRequestPermissionsResult(int requestCode,
String[] permissions, int[] grantResults) {
switch (requestCode) {
case MY_PERMISSIONS_REQUEST_CALL_PHONE: {
// If request is cancelled, the result arrays are empty.
if (grantResults.length > 0
&& grantResults[0] == PackageManager.PERMISSION_GRANTED) {
// permission was granted, yay! Do the
// contacts-related task you need to do.
} else {
// permission denied, boo! Disable the
// functionality that depends on this permission.
}
return;
}
// other 'case' lines to check for other
// permissions this app might request.
}
}
答案 1 :(得分:0)
您可以通过Intent
完成public void dialClick (View v) {
phone = edtPhone.getText().toString();
Uri uri = Uri.parse("tel: " + phone);
it = new Intent(Intent.ACTION_DIAL);
it.setData(uri);
startActivity(it);
}
答案 2 :(得分:0)
您需要在运行时添加权限才能进行调用,我建议使用以下库,因为在执行时实现权限要容易得多。