Question

假设我有一个简单的类型：

public class Report
{
    public Report()
    {
        BirthDate = new Element();
        BirthPlace = new Element();
    }

    public Element BirthDate { get; set; }
    public Element BirthPlace { get; set; }
}

public class Element
{
    [XmlAttribute("published")]
    public bool Published { get; set; }
    [XmlText]
    public string Value { get; set; }
}

我为序列化目的定义了简单的扩展方法：

public static class TheHelper
{
    public static string Serialize<T>(this T source, Encoding encoding)
    {
        MemoryStream memoryStream = new MemoryStream();
        XmlSerializer xs = new XmlSerializer(typeof(T));
        XmlTextWriter xmlTextWriter = new XmlTextWriter(memoryStream, encoding);

        xs.Serialize(xmlTextWriter, source);
        memoryStream = (MemoryStream)xmlTextWriter.BaseStream;
        return encoding.GetString(memoryStream.ToArray());
    }
}

创建示例Report对象时，接下来将其序列化为xml格式：

Report r = new Report();
r.BirthDate.Published = true;
r.BirthDate.Value = DateTime.Now.AddYears(-1000).ToString("yyyy-MM-dd");
r.BirthPlace.Published = false;
r.BirthPlace.Value = "K-PAX";

string xml = r.Serialize(Encoding.UTF8);

创建如下所示的输出文档：

<?xml version="1.0" encoding="utf-8"?>
<Report xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
    <BirthDate published="true">1011-04-07</BirthDate>
    <BirthPlace published="false">K-PAX</BirthPlace>
</Report>

但我想使用名为 xml：lang 的特殊属性添加language identification：

<?xml version="1.0" encoding="utf-8"?>
<Report xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
    <BirthDate published="true" xml:lang="en-GB">1011-04-07</BirthDate>
    <BirthDate published="true" xml:lang="kp-AX">07.04.1011</BirthDate>
    <BirthPlace published="false" xml:lang="en-GB">K-PAX</BirthPlace>
    <BirthPlace published="false" xml:lang="kp-AX">k_p4x</BirthPlace>
</Report>

实现这一目标的聪明方法是什么？我有为en-GB和kp-AX ..语言定义的资源。如何修改和创建Report对象，使多个带有不同xml-lang属性的标记可以使用XmlSerializer进行序列化？

问候。

Answer 1

这应该有效：

public class Element
{
    [XmlAttribute("published")]
    public bool Published { get; set; }
    [XmlAttribute("xml:lang", DataType = "language")]
    public string Language { get; set; }
    [XmlText]
    public string Value { get; set; }
}

如果你想使用CultureInfo类，你可以创建一个属性并使用XmlIgnore属性上的CultureInfo属性，并有一个可以转换它的附加字符串属性，就像在这个LocalizableString示例：

/// <summary>
/// The language of the <see cref="Value"/>
/// </summary>
[XmlIgnore]
public CultureInfo Language { get; set; }

/// <summary>Used for XML serialization.</summary>
/// <seealso cref="Language"/>
[XmlAttribute("xml:lang", DataType = "language")]
public string LanguageString
{
    get { return (Language == null || string.IsNullOrEmpty(Language.ToString())) ?
             null : Language.ToString(); }
    set { Language = string.IsNullOrEmpty(value) ?
             CultureInfo.InvariantCulture : new CultureInfo(value); }
}

使用内置xml序列化机制时xml标记的语言标识

1 个答案: