我正在使用PHP,JS,Axios和Ajax为instagram之类的应用程序提供类似功能。我能够正确启动想要单击要显示为帖子的特定a标签的click事件处理程序。我在执行ajax调用后收到的响应不允许我检查响应的状态。我从我的php文件中传递了$ response ['status'] =“ liked”,但是我通过ajax调用获得的数据变量却不正确。
我首先使用jquery制作了该功能,但想使用axios来避免jquery框架大小带来的较长加载时间。
我尝试使用res.data ['status']选择状态,但这也不起作用。我似乎得到一个结合了JSON响应的数组。
// this selects the exact like button for the post I want to like using
// the data attribute id
let btn = document.querySelector("a.like");
btn.addEventListener("click", function(e){
let postId = this.dataset.id;
let link = this;
console.log("test");
axios.post('ajax/likePost.php',{
postId : postId
})
.then (function (res){
console.log(res);
if (res.data == "liked") {
console.log("we zitten ion de liked");
let likes = link.nextSibling.innerHTML;
link.children.src = "images/liked.svg";
likes++;
link.nextSibling.innerHTML=likes;
} else {
console.log("we zitten ion de niet liked");
let likes = link.nextSibling.innerHTML;
link.children.src = "images/like.svg";
likes--;
link.nextSibling.innerHTML=likes;
}
})
.catch(function (error) {
console.log(error);
});
e.preventDefault();
});
// this is the php file
<?php
# require bootstrap
require_once("../bootstrap/bootstrap.php");
# check if a session is running with the correct email
if (isset($_SESSION['email'])) {
//User is logged in, no redirect needed!
} else {
//User is not logged in, redirect to login.php!
header("location: login.php");
}
# connect to the database
$conn = Db::getConnection();
# get clicked post info from database
$data = json_decode(file_get_contents("php://input"), true);
//get the postId
$postId = $data['postId'];
var_dump($data);
# create empty response array
$response = [];
# get user info from database (get user id based on the session cookie email)
$sessionEmail = $_SESSION['email'];
$statement = $conn->prepare("SELECT * from user where email = :sessionEmail");
$statement->bindParam(":sessionEmail", $sessionEmail);
$statement->execute();
$currentUser = $statement->fetch(PDO::FETCH_ASSOC);
$userId = $currentUser['id'];
# check if a record exists in the likes table where the current post's id and current user's id are available
$likeStatement = $conn->prepare("SELECT count(*) as count from likes where post_id = :postId AND user_id = :userId");
$likeStatement->bindParam(":postId", $postId);
$likeStatement->bindParam(":userId", $userId);
$likeStatement->execute();
$recordAmount = $likeStatement->fetch(PDO::FETCH_ASSOC);
# if 0 records found => insert new record into the likes table with the current post id, user id en a true liked status
if ($recordAmount['count'] == 0) {
# first like, so set liked_status to 1
$liked_status = 1;
# insert new record
$insertLikeStatement = $conn->prepare("INSERT INTO likes (post_id, user_id, liked_status) values (:post_id, :user_id, :liked_status)");
$insertLikeStatement->bindParam(":post_id", $postId);
$insertLikeStatement->bindParam(":user_id", $userId);
$insertLikeStatement->bindParam(":liked_status", $liked_status);
$insertLikeStatement->execute();
$response['status'] = 'liked';
} else {
# check if liked status is true or false
$getLikeStatusStatement = $conn->prepare("SELECT liked_status from likes where post_id = :postId AND user_id = :userId");
$getLikeStatusStatement->bindParam(":postId", $postId);
$getLikeStatusStatement->bindParam(":userId", $userId);
$getLikeStatusStatement->execute();
$currentLikedStatus = $getLikeStatusStatement->fetch(PDO::FETCH_ASSOC);
# if post is liked (liked_status 1) change status || if post is not liked, change status
if ($currentLikedStatus['liked_status'] == 1) {
$liked_status = 0;
$response['status'] = 'unliked';
} else {
$liked_status = 1;
$response['status'] = 'liked';
}
#update record to contain new liked_status
$updateStatement = $conn->prepare("update likes set liked_status= :liked_status where post_id = :postId AND user_id = :userId");
$updateStatement->bindParam(":postId", $postId);
$updateStatement->bindParam(":userId", $userId);
$updateStatement->bindParam(":liked_status", $liked_status);
$updateStatement->execute();
}
header('Content-Type: application/json');
echo json_encode($response);
```
```
// my output in my console when I log the res (response) from the ajax
// call
array(1) {
["postId"]=>
string(2) "22"
}
{"status":"liked"}
```
I want to get back the status of the like button so I can change the likes number and the image for the button.
答案 0 :(得分:1)
您的PHP不仅回显了json响应,而且回显了
。List<string> fileNames = null;
List<string> fileExtensions = null;
private void btn_list_Click(object sender, EventArgs e)
{
using (FolderBrowserDialog fbd = new FolderBrowserDialog())
{
if (fbd.ShowDialog() == DialogResult.OK)
{
lbl_path.Text = fbd.SelectedPath;
fileNames = Directory.GetFiles(fbd.SelectedPath).ToList();
fileExtensions = fileNames.Select(item =>
Path.GetExtension(item).Replace(".", "")).Distinct().OrderBy(n => n).ToList();
listBox_name..DataSource = fileNames.Select(f => Path.GetFileName(f)).ToList();
listBox_ex.DataSource = fileExtensions;
}
}
}
private void btn_CreateFolder_Click(object sender, EventArgs e)
{
using (FolderBrowserDialog fbd = new FolderBrowserDialog())
{
if (fbd.ShowDialog() == DialogResult.OK)
{
lbl_pathCreated.Text = fbd.SelectedPath;
fileExtensions.ForEach(item =>
Directory.CreateDirectory(Path.Combine(fbd.SelectedPath, item)));
}
}
}
归因于array(1) {
["postId"]=>
string(2) "22"
}
。尝试删除它。