从Django应用访问多个架构

Question

说我有一个带有const myClass = require('../index'); const myService = require('../myService'); describe('service-tests - index', () => { let doOtherStuffMock; beforeAll(() => { doOtherStuffMock = jest.spyOn(myService.prototype, 'doOtherStuff'); }); it('mocks doOtherStuff one way', async () => { doOtherStuffMock.mockResolvedValue('I am a mocked value'); const result = await myClass.doStuff((err, data) => data); expect(result).toBe("I am a mocked value"); }); it('mocks doOtherStuff another way', async () => { doOtherStuffMock.mockResolvedValue('I am DIFFERENT mocked value'); const result = await myClass.doStuff((err, data) => data); expect(result).toBe('I am DIFFERENT mocked value'); }); }); 和schema1的Postgres数据库。我希望我的Django应用程序schema2可以同时访问myapp和schema1中的数据。

我几乎找到了一种使用schema2（基于this answer的解决方法），直到我意识到这破坏了Django admin，并因此破坏了其他功能。

我试图在模型的app_labels中指定自定义app_label：

Meta

然后，我为myapp实现了两个单独的路由器，每个路由器都路由到以下一种模式：

class OneModel(models.Model):
    gid = models.AutoField(primary_key=True)
    name = models.CharField(max_length=40, blank=True, null=True)

    class Meta:
        managed = False
        db_table = 'one_table'
        app_label = 'myapp_to_schema1' 

class AnotherModel(models.Model):
    gid = models.AutoField(primary_key=True)
    color = models.CharField(max_length=40, blank=True, null=True)

    class Meta:
        managed = False
        db_table = 'another_table'
        app_label = 'myapp_to_schema2' 

最后，数据库的设置如下：

class MyappToSchema1Router:        
    def db_for_read(self, model, **hints):
        if model._meta.app_label == 'myapp_to_schema1':
            return 'schema1'
        return None

    def db_for_write(self, model, **hints):
        if model._meta.app_label == 'myapp_to_schema1':
            return 'schema1'
        return None

    def allow_migrate(self, db, app_label, model_name=None, **hints):
        if app_label == 'myapp_to_schema1':
            return db == 'schema1'
        return None

class MyappToSchema2Router:        
    def db_for_read(self, model, **hints):
        if model._meta.app_label == 'myapp_to_schema2':
            return 'schema2'
        return None

    def db_for_write(self, model, **hints):
        if model._meta.app_label == 'myapp_to_schema2':
            return 'schema2'
        return None

    def allow_migrate(self, db, app_label, model_name=None, **hints):
        if app_label == 'myapp_to_schema2':
            return db == 'schema2'
        return None

如前所述，这很好用（即我可以使用DATABASES = { 'default': { }, 'schema1': { 'ENGINE': 'django.contrib.gis.db.backends.postgis', 'OPTIONS': { 'options': '-c search_path=schema1' }, 'NAME': 'mydb', 'USER': secrets.USER, 'PASSWORD': secrets.PASSWORD, 'HOST': 'my.host.address', 'PORT': '5432', }, 'schema2': { 'ENGINE': 'django.contrib.gis.db.backends.postgis', 'OPTIONS': { 'options': '-c search_path=schema2' }, 'NAME': 'mydb', 'USER': secrets.USER, 'PASSWORD': secrets.PASSWORD, 'HOST': 'my.host.address', 'PORT': '5432', }, } } 和OneModel.objects.all()在Python shell中访问两个模型），但是当访问Django管理员时，出现错误{{1} }

从单个应用程序访问多个架构的正确方法是什么？